A vertical pole is placed in the ground at a campsite outside Salt Lake City, Utah. One winter day, 16 of the pole is in the gro
1 answer:
Answer:
<em>Length of the pole = 10.8 ft</em>
<em>Depth of the snow = 7.2 ft </em>
Step-by-step explanation:
The correct question is
A vertical pole is placed in the ground at a campsite outside Salt Lake City, Utah. One winter day, 1/6 of the pole is in the ground, 2/3 of the pole is covered in snow, and 1.8 ft is above the snow. How long is the pole, and how deep is the snow.
The fraction of the pole in the ground = 1/6
The fraction of the pole in the snow = 2/3
The length of the pole above the snow = 1.8 ft
Total fraction of the length of the pole = 1
For the fraction of the length above the snow, we solve as
1/6 + 2/3 + = 1
= 1 - 1/6 - 2/3 = 1/6
This means that the length of the pole above the snow 1.8 ft = 1/6 of the length of the pole.
Also, the fraction of the pole in the ground = 1/6
this means that the length of the pole in the ground = 1.8 ft
If 1/6 of the length of pole is 1.8 ft,
the length of the pole = 1.8 ft x 6 = <em>10.8 ft</em>
Length of the pole in the snow = 2/3 of 10.8 = 2/3 x 10.8 = 7.2 ft
this means that the the snow is <em>7.2 ft deep </em>
You might be interested in
The child crawled 18 meters in 823 seconds.
Given:
A child is crawling at a pace of 176 inches every 3.37 minutes.
To find:
The distance covered (in meters) by a child in 823 seconds.
Solution:
Distance covered by a child in 3.37 minutes = 176 inches
Distance covered by a child in a 1 minute =
1 minute = 60 seconds
Distance covered by a child in 60 seconds =
Distance covered by a child in a 1 second:
Distance covered by a child in 823 seconds:
In 1 meter there are 39.37 inches.
The child crawled 18 meters in 823 seconds.
Learn more about the unitary method here: