Write as an expression: The product of a number b and the sum of 8 and a number c

Find the perimeter of a triangle with vertices A(3, 1), B(2, -1), and C(-3, 2). Leave

natulia [17]

The perimeter of triangle is: 14.15 units

Step-by-step explanation:

First of all we have to find the lengths of sides of triangles

Given

A(3, 1), B(2, -1), and C(-3, 2)

The distance formula will be used to find the lengths of sides

$d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\$

So,

$AB = \sqrt{(2-3)^2+(-1-1)^2}\\=\sqrt{(-1)^2+(2)^2}\\=\sqrt{1+4}\\=\sqrt{5}\\=2.24\ unitsBC = \sqrt{(-3-2)^2+(2+1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\= 5.83\ units\\AC = \sqrt{(-3-3)^2+(2-1)^2}\\=\sqrt{(-6)^2+(1)^2}\\=\sqrt{36+1}\\=\sqrt{37}\\=6.08\ units$

The perimeter of triangle will be:

$P = AB+BC+AC\\= 2.24+5.83+6.08\\=14.15\ units$

Hence,

The perimeter of triangle is: 14.15 units

Keywords: Triangle Perimeter

Learn more about perimeter at:

#LearnwithBrainly

7 0

2 years ago

Move two choices to the blanks to correctly complete the sentences.

Pavel [41]

Answer:

(A) There should have been 5 outcomes of HT

(B) The experimental probability is greater than the theoretical probability of HT.

Step-by-step explanation:

Given

$S = \{HH,HT,TH,TT\}$ -- Sample Space

$n(S) = 4$ --- Sample Size

Solving (a); theoretical outcome of HT in 20 tosses

First, calculate the theoretical probability of HT

$P(HT) = \frac{n(HT)}{n(S)}$

$P(HT) = \frac{1}{4}$

Multiply this by the number of tosses

$P(HT) * n= \frac{1}{4} * 20$

$P(HT) * n= 5$

Solving (b); experimental probability of HT

Here, we make use of the table

$P(HT) = \frac{n(HT)}{n(S)}$

$P(HT) = \frac{6}{20}$

$P(HT) = 0.30$ ---- Experimental Probability

In (a), the theoretical probability is:

$P(HT) = \frac{1}{4}$

$P(HT) = 0.25$ ---- Experimental Probability

By comparison;

$0.30 > 0.25$

6 0

3 years ago

What is the interquartile range of this data set 2, 5, 9, 11, 18, 30, 42, 48, 71, 73, 81

Shtirlitz [24]

Answer:

I believe the answer is 62.

Step-by-step explanation:

Hope my answer has helped you!

8 0

3 years ago

Please help! acellus

ch4aika [34]

Answer:

The number that belongs in the green box is equal to 909.

General Formulas and Concepts:
Algebra I

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Trigonometry

[Right Triangles Only] Pythagorean Theorem:
$\displaystyle a^2 + b^2 = c^2$

a is a leg
b is another leg
c is the hypotenuse

Step-by-step explanation:

Step 1: Define

Identify given variables.

a = 30

b = 3

c = x

Step 2: Find x

Let's solve for the general equation that allows us to find the hypotenuse:

[Pythagorean Theorem] Square root both sides [Equality Property]:
$\displaystyle \begin{aligned}a^2 + b^2 = c^2 \rightarrow c = \sqrt{a^2 + b^2}\end{aligned}$

Now that we have the formula to solve for the hypotenuse, let's figure out what x is equal to:

[Equation] Substitute in variables:
$\displaystyle \begin{aligned}c & = \sqrt{a^2 + b^2} \\x & = \sqrt{30^2 + 3^2}\end{aligned}$
Evaluate:
$\displaystyle \begin{aligned}c & = \sqrt{a^2 + b^2} \\x & = \sqrt{30^2 + 3^2} \\& = \boxed{ \sqrt{909} } \\\end{aligned}$

∴ the hypotenuse length x is equal to √909 and the number under the square root, our answer, is equal to 909.

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Learn more about Trigonometry: brainly.com/question/27707750

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Topic: Trigonometry

3 0

2 years ago

The amount of snow on the ground increased by 4 inches between 4 p.m and 6 p.m. If there was 6 inches of snow on the ground at 4

Vera_Pavlovna [14]

10 inches because at 4 pm it was 6 inches but since it says it increases 4 inches during the times 4 PM through 6 PM it should've gone up another 4 inches. 6 plus 4 equals 10. ?????????

6 0

3 years ago