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krok68 [10]
3 years ago
8

Please answer my question if you answer it I will surely mark you as the brainliest and if you answer it you will get 30 points

and if you answer it I will rate you

Mathematics
1 answer:
Alika [10]3 years ago
4 0

Answer:

Step-by-step explanation:

1) \frac{tan A + Sin A}{tan A - Sin A}=\frac{\frac{sin A}{cos A}+sinA}{\frac{sinA}{cos A}-sin A}\\\\=\frac{\frac{sin A + Sin A CosA}{Cos A}}{\frac{sinA-sinAcosA}{cosA}}\\\\=\frac{sin A + Sin A CosA}{Cos A}*\frac{cosA}{sinA-sinAcosA}\\\\=\frac{sinA+sinAcosA}{sinA-sinAcosA}\\\\=\frac{sinA(1+cosA)}{SinA(1-cosA)}\\\\\frac{1+cosA}{1-cosA}\\\\=\frac{1+\frac{1}{secA}}{1-\frac{1}{secA}}\\\\=\frac{\frac{secA+1}{secA}}{\frac{secA-1}{secA}}\\\\=\frac{secA+1}{secA-1}

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Step-by-step explanation:

Given

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Required

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