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3 years ago

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Buying the newest phone as soon as it is released when your current phone works perfectly is not a good idea for all but which o

f the following reasons?

Computers and Technology

2 answers:

bixtya [17]3 years ago

5 0

Answer:

You are gonna waste money and it might not be the best idea

Explanation:

Pepsi [2]3 years ago

5 0

Answer:

waste money

Explanation:

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Sub to the channel plz plz

Hunter-Best [27]

Answer:

um

Explanation:

6 0

2 years ago

Read 2 more answers

The L-exclusion problem is a variant of the starvation-free mutual exclusion problem. We make two changes: as many as L threads

vladimir2022 [97]

Answer:

The solution is as follows.

class LFilters implements Lock {

int[] lvl;

int[] vic;

public LFilters(int n, int l) {

lvl = new int[max(n-l+1,0)];

vic = new int[max(n-l+1,0)];

for (int i = 0; i < n-l+1; i++) {

lvl[i] = 0;

}

}

public void lock() {

int me = ThreadID.get();

for (int i = 1; i < n-l+1; i++) { // attempt level i

lvl[me] = i;

vic[i] = me;

// rotate while conflicts exist

int above = l+1;

while (above > l && vic[i] == me) {

above = 0;

for (int k = 0; k < n; k++) {

if (lvl[k] >= i) above++;

}

}

}

}

public void unlock() {

int me = ThreadID.get();

lvl[me] = 0;

}

}

Explanation:

The code is presented above in which the a class is formed which has two variables, lvl and vic. It performs the operation of lock as indicated above.

6 0

3 years ago

Although a tablet can connect to a cellular network, it cannot be used as a

Misha Larkins [42]

Answer:

A tablet can have mobile data such as MetroPCS. But the tablet can not make phone calls or texts.

7 0

3 years ago

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Write the code to produce a for loop that counts down from 20 to 0 by 2’s and prints the number each time it goes through the lo

yulyashka [42]

Explanation:

Count-controlled for loop (Three-expression for loop)

This is by far the most common type. This statement is the one used by C. The header of this kind of for loop consists of a three-parameter loop control expression. Generally it has the form:

for (A; Z; I)

A is the initialisation part, Z determines a termination expression and I is the counting expression, where the loop variable is incremented or dcremented. An example of this kind of loop is the for-loop of the programming language C:

for (i=0; i <= n; i++)

This kind of for loop is not implemented in Python!

Numeric Ranges

This kind of for loop is a simplification of the previous kind. It's a counting or enumerating loop. Starting with a start value and counting up to an end value, like for i = 1 to 100

Python doesn't use this either.

Vectorized for loops

They behave as if all iterations are executed in parallel. This means, for example, that all expressions on the right side of assignment statements get evaluated before the assignments.

Iterator-based for loop

Finally, we come to the one used by Python. This kind of a for loop iterates over an enumeration of a set of items. It is usually characterized by the use of an implicit or explicit iterator. In each iteration step a loop variable is set to a value in a sequence or other data collection. This kind of for loop is known in most Unix and Linux shells and it is the one which is implemented in Python.

Example of a simple for loop in Python:

>>> languages = ["C", "C++", "Perl", "Python"]

>>> for x in languages:

... print(x)

...

C

C++

Perl

Python

>>>

3 0

3 years ago

Determine and prove whether an argument in English is valid or invalid. About Prove whether each argument is valid or invalid. F

yawa3891 [41]

Answer:

Each understudy on the respect roll got an A.

No understudy who got a confinement got an A.

No understudy who got a confinement is on the respect roll.

No understudy who got an A missed class.

No understudy who got a confinement got an A.

No understudy who got a confinement missed class

Explanation:

M(x): x missed class

An (x): x got an A.

D(x): x got a confinement.

¬∃x (A(x) ∧ M(x))

¬∃x (D(x) ∧ A(x))

∴ ¬∃x (D(x) ∧ M(x))

The conflict isn't considerable. Consider a class that includes a lone understudy named Frank. If M(Frank) = D(Frank) = T and A(Frank) = F, by then the hypotheses are overall evident and the end is counterfeit. Toward the day's end, Frank got a control, missed class, and didn't get an A.

Each understudy who missed class got a confinement.

Penelope is an understudy in the class.

Penelope got a confinement.

Penelope missed class.

M(x): x missed class

S(x): x is an understudy in the class.

D(x): x got a confinement.

Each understudy who missed class got a confinement.

Penelope is an understudy in the class.

Penelope didn't miss class.

Penelope didn't get imprisonment.

M(x): x missed class

S(x): x is an understudy in the class.

D(x): x got imprisonment.

Each understudy who missed class or got imprisonment didn't get an A.

Penelope is an understudy in the class.

Penelope got an A.

Penelope didn't get repression.

M(x): x missed class

S(x): x is an understudy in the class.

D(x): x got a repression.

An (ax): x got an A.

H(x): x is on the regard roll

An (x): x got an A.

D(x): x got a repression.

∀x (H(x) → A(x)) a

¬∃x (D(x) ∧ A(x))

∴ ¬∃x (D(x) ∧ H(x))

Real.

1. ∀x (H(x) → A(x)) Hypothesis

2. c is a self-self-assured element Element definition

3. H(c) → A(c) Universal dispatch, 1, 2

4. ¬∃x (D(x) ∧ A(x)) Hypothesis

5. ∀x ¬(D(x) ∧ A(x)) De Morgan's law, 4

6. ¬(D(c) ∧ A(c)) Universal dispatch, 2, 5

7. ¬D(c) ∨ ¬A(c) De Morgan's law, 6

8. ¬A(c) ∨ ¬D(c) Commutative law, 7

9. ¬H(c) ∨ A(c) Conditional character, 3

10. A(c) ∨ ¬H(c) Commutative law, 9

11. ¬D(c) ∨ ¬H(c) Resolution, 8, 10

12. ¬(D(c) ∧ H(c)) De Morgan's law, 11

13. ∀x ¬(D(x) ∧ H(x)) Universal hypothesis, 2, 12

14. ¬∃x (D(x) ∧ H(x)) De Morgan's law, 13

4 0

3 years ago