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professor190 [17]
2 years ago
15

Taryn and lanny were each asked to represent 75% of $1.00

Mathematics
2 answers:
Brrunno [24]2 years ago
8 0

Answer:

The answer, I think would be $0.75 or 75 cents you could do it on a circle graph or a math grid out of 100

Step-by-step explanation:

sergejj [24]2 years ago
6 0

Answer:

75 percent of a dollar is 75 cents so were they each asked to represent that much?

Step-by-step explanation:

sorry confusing question

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Gabe rolled 14 strikes out of 70 attempts. What percent of Gabe's attempts were strikes?
Airida [17]

Answer:

20%

Step-by-step explanation:

14/70x100=20%

5 0
2 years ago
Please Help Me ;-;
ANTONII [103]

slope  = (y2-y1)/(x2-x1)

      =  (2--1)/(5-1)

      = (2+1)/(4)

       =3/4


The point slope from of a line is

y-y1 = m(x-x1)

y--1 = 3/4 (x-1)

y+1 = 3/4 (x-1)

3 0
3 years ago
Match each quadratic equation with the best way to solve it. 1. 5x2 + 12x - 3 = 0 solve by square root method 2. x2 - 4x = 8 sol
Ksivusya [100]
<span>The best way to solve each equation is:
 
</span> 1) 5x2 + 12x - 3 = 0 -----> solve by quadratic formula 
 2) 4x2 - 25 = 0 -----------> solve by square root method 
 3) x2 - 5x + 6 = 0 --------> solve by factoring
 4) x2 - 4x = 8 -------------> solve by completing the square 

8 0
2 years ago
An article describes an experiment to determine the effectiveness of mushroom compost in removing petroleum contaminants from so
alexgriva [62]

Solution :

Let p_1 and p_2  represents the proportions of the seeds which germinate among the seeds planted in the soil containing 3\% and 5\% mushroom compost by weight respectively.

To test the null hypothesis H_0: p_1=p_2 against the alternate hypothesis  H_1:p_1 \neq p_2 .

Let \hat p_1, \hat p_2 denotes the respective sample proportions and the n_1, n_2 represents the sample size respectively.

$\hat p_1 = \frac{74}{155} = 0.477419

n_1=155

$p_2=\frac{86}{155}=0.554839

n_2=155

The test statistic can be written as :

$z=\frac{(\hat p_1 - \hat p_2)}{\sqrt{\frac{\hat p_1 \times (1-\hat p_1)}{n_1}} + \frac{\hat p_2 \times (1-\hat p_2)}{n_2}}}

which under H_0  follows the standard normal distribution.

We reject H_0 at 0.05 level of significance, if the P-value or if |z_{obs}|>Z_{0.025}

Now, the value of the test statistics = -1.368928

The critical value = \pm 1.959964

P-value = $P(|z|> z_{obs})= 2 \times P(z< -1.367928)$

                                     $=2 \times 0.085667$

                                     = 0.171335

Since the p-value > 0.05 and $|z_{obs}| \ngtr z_{critical} = 1.959964$, so we fail to reject H_0 at 0.05 level of significance.

Hence we conclude that the two population proportion are not significantly different.

Conclusion :

There is not sufficient evidence to conclude that the \text{proportion} of the seeds that \text{germinate differs} with the percent of the \text{mushroom compost} in the soil.

8 0
3 years ago
Which of the following correctly shows the property of distribution?
Elan Coil [88]
B is correct.
A. 5(x-2)= 5x-10
B. 4(x+3)= 4x + 12
C. 3(x+1)= 3x+3
D. 2(x+7) = 2x + 14
7 0
3 years ago
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