What are the common multiples of 2 3 and 5
1 answer:
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Answer:
4 mph
Step-by-step explanation:
The average speed of an object is given by the total distance covered by the time taken:
where
d is the total distance covered
t is the time taken
in the first part, the person runs for 0.4 hours at a speed of 7 mph, so the distance covered in the 1st part is
Then the distance covered in the second part is , so the total distance is
(1)
The total time elapsed is 0.4 hours (first part) + 0.8 hours (second part), so
So we can write the average speed as
(1)
We want the average speed to be 5 mph,
v = 5 mph
Therefore we can rearrange eq.(1) to find d2:
And therefore, the speed in the second part must be
Answer:
False, counterexample below
Step-by-step explanation:
Denote the unit vectors of R^3 by . Now consider
and
. We have that
. Also, the vector
is not a linear combination of
because any linear combination of these two vectors will have third coordinate zero, but v_3 has third coordinate 1 so they can't be equal.
However, the set is not linearly independent, because
is a non-trivial linear combination of these vectors that equals zero.