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Svetradugi [14.3K]

3 years ago

6

The following table shows ordered pairs for a linear function x. Which one of the following equations was used to generate this

table?

1 answer:

Taya2010 [7]3 years ago

7 0

Answer:

b

5x+3

Step-by-step explanation:

5×3=15+4=18

5×4=20+3=23

5×8=40+3=43

5×10=50+3=53

hope this helps

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The volume of this prism

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Y intercept of 3x+5y=-30

ELEN [110]

Substitute x=0
5y=-30
y=-6 is the y intercept

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If a person can carry 40 pounds, and a group of people want to carry 86 pounds of stuff, how many people are necessary to carry

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Answer:

3 people

Step-by-step explanation:

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3 years ago

After the party, 3 1⁄4 pecan pies remained. The next day, Edward's family ate 1 1⁄4 of a pie. How many pecan pies were left?

vlabodo [156]

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2

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Kayla and latasha work for a department store the amount of sales they made over the last year was collected monthly in the data

tresset_1 [31]

Based on the information represented by the boxplot ;

Latasha's lowest sale amount = 50

Kayla's median is between 200 and 300

Latasha has a greater spread due to higher IQR value

1.) <em><u>The Lowest amount of sale made by Latasha in one month </u></em>

The minimum value is denoted by the starting position of the lower whisker on a boxplot.

Lowest amount of sale made by Latasha = 50

2.) <em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>made</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>Kayla</u></em><em><u> </u></em><em><u>:</u></em>

50% of sales made marks the median value in a boxplot, it is denoted by the vertical line in between the box.

50% of sales made by Kayla is between 200 and 300

With median sale value being 250

3.) <em><u>Spread</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>middle</u></em><em><u> </u></em><em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>:</u></em>

The measure of spread of the middle 50% of a distribution on a boxplot is the Interquartile range (IQR) of the distribution

IQR = Upper Quartile (Q3) - Lower quartile(Q1)

<u>For Latasha</u> :

Q3 = 450 (Endpoint of the box)
Q1 = 150 (starting point of the box)

IQR = 450 - 150 = 300

<u>For</u><u> </u><u>Kayla</u><u> </u><u>:</u><u> </u>

Q3 = 375 (Endpoint of the box)
Q1 = 100 (starting point of the box)
IQR = 375 - 100 = 275

Since, Latasha's IQR is greater than Kayla's, then Latasha has a greater mid 50% spread than Kayla.

Learn more :brainly.com/question/24582786

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2 years ago