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4 years ago

2. How fast would a 0.25 kg football have to be traveling to have the same momentum as a 0.05 kg bullet travelling 500 m/s?

1 answer:

3 0

Their momentum would be equal. so,
m1v1 = m2v2
0.25 * v1 = 0.05 * 500
v1 = 25 / 0.25
v1 = 100 m/s

In short, Your Answer would be 100 m/s

Hope this helps!

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the variables x and y have a proportional relatinship and y=2/5 when x=5/8 which equation represents this relationship

mafiozo [28]

The equation is y = 16/25 x

lets find the proportional relationship,

y = kx

2/5 = k * 5/8

k = (2/5) / (5/8)

k = 16/25

so if k, constant is 16/25

equation is:

y = 16/25 x

<h3>What are proportional relationships?</h3>

Proportional relationships are relationships between two variables where their ratios are equivalent. Another way to think about them is that, in a proportional relationship, one variable is always a constant value times the other. That constant is know as the "constant of proportionality".

<h3>How do you find the proportional relationship in an equation?</h3>

The equation that represents a proportional relationship, or a line, is y = k x , where is the constant of proportionality. Use k = y x from either a table or a graph to find k and create the equation.

To learn more about proportional relationship from the given link

brainly.com/question/2143065

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1 year ago

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Paul can walk 15 steps in 5 minutes. How long does it take Paul to walk 75 steps at the same speed? I got 25 minutes am i right?

lina2011 [118]

The best way to solve this one is with a proportion:

(15 steps) / (5 minutes) = (75 steps) / ('x' minutes)

Cross-multiply the proportion: 15 x = 5 x 75

Divide each side by 15 : x = 5 x 5 = <em>25 minutes</em>.

You are correct, and Paul walks very slowly.

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3 years ago

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What are the roots of the polynomial equation x^3-5x+5=2x^2-5? Use a graphing calculator and a system of equations. Round nonint

leonid [27]

The right answer is c. –2.24, 2, 2.24

This question needs to be solved in two ways. First, using a graphing calculator. Next, using a system of equations.

1. Using a graphing calculator.

We have the following polynomial equation:

$x^3-5x+5=2x^2-5$

By ordering this equation we have:

$x^3-2x^2-5x+10=0$

So, we can say that this equation comes from a function given by:

$f(x)=x^3-2x^2-5x+10$

Thus, by plotting this function, we have that the graph of this function is indicated in Figure 1. By zooming, we can see, in Figure 2, that the roots of the polynomial equation are the x-intercepts of $f(x)$ which are:

$x_{1}=-2.236 \\ \\ x_{2}=2 \\ \\ x_{3}=2.236$

Finally, rounding noninteger roots to the nearest hundredth we have:

$\boxed{Root_{1}=-2.24} \\ \\ \boxed{Root_{2}=2} \\ \\ \boxed{Root_{3}=2.24}$

2. Using a system of equations.

The ordered equation is:

$x^3-2x^2-5x+10=0$

By arranging to factor out we have:

$x^3-5x-2x^2+10=0$

Then, by factoring:

$x(x^2-5)-2(x^2-5)=0$

Term $(x^2-5)$ is a common factor, thus:

$(x-2)(x^2-5)=0 \\ \\ (x-2)(x-\sqrt{5})(x+\sqrt{5})=0 \\ \\ Finally: \\ \\ \boxed{Root_{1}=-\sqrt{5}=-2.24} \\ \\ \boxed{Root_{2}=2} \\ \\ \boxed{Root_{3}=\sqrt{5}=2.24}$

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Write an equation that shows the equivalency between meters and gigameters.

Anastasy [175]

Below is an equation that shows the equivalency between meters andGigameters:

$10 ^{9} m = 1 Gm$

The conversion factor should be used to convert from meters toGigameters should be:

$\frac{1 Gm}{10 ^{9} m }$

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How to find the area of a regular figure

Lady_Fox [76]

U multiply two sides

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