Answer:
You want to solve for x, the first thing you need to do is distribute
The 2 through the x+4 then the other 2 through the -8-x
2(x+4)= 2x+8
2(-8-x)= -16-2x
2x+8=-16-2x-2x (combine like terms on the right side)
2x+8=-16-4x (now subtract 8 from each side)
2x=-24-4x (8-8=0, -16-8=-24) (now add 4x to each side)
6x=-24 (-4x+4x=0, 2x+4x=6x), (divide each side by 6)
x=-4 (6/6=1, -24/6=-4)
x=-4
Hope this helps ;)
Answer:
The sum of the first 650 terms of the given arithmetic sequence is 2,322,775
Step-by-step explanation:
The first term here is 4
while the nth term would be ai = a(i-1) + 11
Kindly note that i and 1 are subscript of a
Mathematically, the sum of n terms of an arithmetic sequence can be calculated using the formula
Sn = n/2[2a + (n-1)d)
Here, our n is 650, a is 4, d is the difference between two successive terms which is 11.
Plugging these values, we have
Sn = (650/2) (2(4) + (650-1)11)
Sn = 325(8 + 7,139)
Sn = 325(7,147)
Sn = 2,322,775
Answer:
3. is 3 (m - 16)(m + 4)
7. is also 3. (2x + 5)(3x - 5)
12. is 4 (x - 6)(x - 4)
the last one is i dont know
Answer:
k = –10
Step-by-step explanation:
From the question given above, the following data were obtained:
f(x) = x³ – 6x² – 11x + k
Factor => x + 2
Value of K =?
Next, we shall obtained the value of x from x + 2. This is illustrated below:
x + 2 = 0
Collect like terms
x = 0 – 2
x = –2
Finally, we shall determine the value of k as illustrated below:
f(x) = x³ – 6x² – 11x + k
x = –2
Thus,
f(–2) = 0
x³ – 6x² – 11x + k = 0
(–2)³ – (–2)² – 11(–2) + k = 0
–8 – (4) + 22 + K = 0
–8 – 4 + 22 + K = 0
10 + k = 0
Collect like terms
k = 0 – 10
k = –10
Thus, the value of k is –10
If a(n) = (39n^4 -506n^3 + 2341n^2 - 4610n + 3416) / 8 then
<span>a(1) = 85 </span>
<span>a(2) = 17 </span>
<span>a(3) = 19 </span>
<span>a(4) = 4 </span>
<span>a(5) = 2</span>
