Answer:
90 stamps from Canada, 108 stamps from the United States, and 135 stamps from the Rest of the World
Step-by-step explanation:
Since this is a problem of proportion we can use the Rule of three to solve this. We do this by multiplying the diagonal available values and dividing by the third value in order to get the missing variable, which in this case would be the number of stamps in the other country. Like so...
1.5 <=====> 135 stamps
1.2 <=====> x stamps (United States)
(1.2 * 135) / 1.5 = 108 stamps (United States)
1.5 <=====> 135 stamps
1 <=====> x stamps (Canada)
(1 * 135) / 1.5 = 90 stamps (Canada)
Finally, we can see that Katie had 90 stamps from Canada, 108 stamps from the United States, and 135 stamps from the Rest of the World. All creating a ratio or 1:1.2:1.5
Answer:
3*10^5 or 300,000 cant remember witch one it is
Step-by-step explanation:
1.5*10^2= 150
2*10^3=2,000
150*2000=300,000
3*10^5
Answer:
Step-by-step explanation:
What subject is that?
Answer:
first option
Step-by-step explanation:
Given
f(x) = 
← factorise the numerator
= 
← cancel (x + 4) on numerator/ denominator
= 2x - 3
Cancelling (x + 4) creates a discontinuity ( a hole ) at x + 4 = 0, that is
x = - 4
Substitute x = - 4 into the simplified f(x) for y- coordinate
f(- 4) = 2(- 4) - 3 = - 8 - 3 = - 11
The discontinuity occurs at (- 4, - 11 )
To obtain the zero let f(x) = 0, that is
2x - 3 = 0 ⇒ 2x = 3 ⇒ x = 
There is a zero at ( , 0 )
Thus
discontinuity at (- 4, - 11 ), zero at ( , 0 )
Answer:
the probability that two 18 year old boys chosen at random will have heights greater than 185cm is 0.403
Step-by-step explanation:
P( x > 193) = 0.15
= 1- p(x less than or equal 193)
= 1 -p( z < (x- u) /sigma)
= 1- p( z< (193 - 187)/ sigma)
= 1- p( z< 6/ sigma)
P(z< 6/sigma) = 1 - 0.15
P(z < 6/sigma)= 0.85
6/sigma =1.036
Sigma= 6/1.036
Sigma= 5.79
P( x> 185) = 1- p( x< 185)
= 1- p (z < (185- 187)/5.79)
= 1- p( z< -0.345)
= 1- 0.365
= 0.635
P (x> 185) = 0.635 × 0.635
=0.403
