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strojnjashka [21]
3 years ago
13

A high school reports that its​ students' SAT scores were down by 8​% in one year. The next​ year, however, the test scores rose

by 18​%. The high school principal​ announces, "Overall, test scores have improved by 10​% over the past two​ years."
Mathematics
1 answer:
krek1111 [17]3 years ago
6 0

Answer:

B

1.09 is the improvement in scores

Step-by-step explanation:

Here is the remaining part of the question : Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The statement is true because 18 - 10 = 8 and the percentage improvement is given by the difference in the percentages of the increase and decrease. B. The statement is false because the reference values for the decrease and increase are not the same. The true improvement over the past two years is (Simplify your answer. Type an integer or decimal rounded to the nearest hundredth as needed.)

let a = scores

If scores decreased by 8% last year, scores that year was (100 - 8%) = 92% = 0.92

scores last year = 0.92a

If scores increased by 18%. It means the score this year is 0.92a x 1.18 = 1.086a

Improvement in scores 1.09

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The product of the forth and tenth terms of an arithmetic progression is 189. Dividing the eighth term by the third term gives 2
babymother [125]

Answer:

The first term is 3, and the common difference is 2.

Step-by-step explanation:

The nth term of an arithmetic sequence is:

a = a₀ + d (n − 1)

We are given two equations:

a₄ a₁₀ = 189

a₈ = 2 a₃ + 3

Where:

a₃ = a₀ + d (3 − 1) = a₀ + 2d

a₄ = a₀ + d (4 − 1) = a₀ + 3d

a₈ = a₀ + d (8 − 1) = a₀ + 7d

a₁₀ = a₀ + d (10 − 1) = a₀ + 9d

Substituting:

(a₀ + 3d) (a₀ + 9d) = 189

a₀ + 7d = 2 (a₀ + 2d) + 3

Two equations, two variables.  First, simplify:

a₀² + 12 a₀ d + 27d² = 189

0 = a₀ − 3d + 3

Solve for a₀ in the second equation and substitute into the first:

a₀ = 3d − 3

(3d − 3)² + 12 (3d − 3) d + 27d² = 189

9d² − 18d + 9 + 36d² − 36d + 27d² = 189

72d² − 54d − 180 = 0

4d² − 3d − 10 = 0

4d² − 3d − 10 = 0

(d − 2) (4d + 5) = 0

d = -1.25 or 2

a₀ = 3d − 3

a₀ = -6.75 or 3

If a₀ = -6.75 and d = -1.25:

a₄ a₁₀ = -10.5 × -18 = 189

a₈ / a₃ = -15.5 / -9.25 = 1 R 6.25

Extraneous solution

If a₀ = 3 and d = 2:

a₄ a₁₀ = 9 × 21 = 189

a₈ / a₃ = 17 / 7 = 2 R 3

The first term is 3, and the common difference is 2.

6 0
3 years ago
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