Answer:
D. x = 10, m<TRS = 60°
Step-by-step explanation:
m<QRS = 122° (given)
m<QRT = (7x - 8)° (given)
m<TRS = (6x)° (given)
m<QRT + m<TRS = m<QRS (angle addition postulate)
(7x - 8)° + (6x)° = 122° (substitution)
Solve for x
7x - 8 + 6x = 122
Add like terms
13x - 8 = 122
13x = 122 + 8
13x = 130
x = 130/13
x = 10
✔️m<TRS = (6x)°
Plug in the value of x
m<TRS = (6*10)° = 60°
Given:
Area of a circle, A=50.265 sq. units.
Radius of circle, r = 4 units.
To find:
The value of π to the nearest thousandth.
Solution:
Formula for area of a circle is
Now, using 
expression, we can find the value of π.
Approximate the value to the nearest thousandth (three digits after decimal).
Therefore, the approximated value of π is 3.142.
∆volume = 4/3 *pi * (R^3 -r^3 )
= 4/3 *pi*((6)^3 -(3)^3)
= 252*pi
= 791.68 m^3
27^10-9^14
=3^30 - 3^28
=3^28 (3^2-1)
=3^28 ·8
=2^27 ·3·8
=3^27 · 24 is divisible by 24
