(x - a)^2 + (y - b)^2 = (y - d)^2
<span>x^2 - 2ax + a^2 + y^2 - 2by + b^2 = y^2 - 2dy + d^2 </span>
<span>Subtract y^2 from both sides... </span>
<span>x^2 - 2ax + a^2 - 2by + b^2 = -2dy + d^2 </span>
<span>Now I would just substitute in the the values (a = -4, b = 17/8, d = 15/8)... </span>
<span>x^2 - 2(-4)x + (-4)^2 - 2(17/8)y + (17/8)^2 = -2(15/8)y + (15/8)^2 </span>
<span>Simplify... </span>
<span>x^2 + 8x + 16 - (17/4)y + 289/64 = -(15/4)y + 225/64 </span>
<span>Add (17/4)y to both sides... </span>
<span>x^2 + 8x + 16 + 289/64 = (2/4)y + 225/64 </span>
<span>x^2 + 8x + 16 + 289/64 = (1/2)y + 225/64 </span>
<span>Subtract 225/64 from both sides... </span>
<span>x^2 + 8x + 16 + 1 = (1/2)y </span>
<span>x^2 + 8x + 17 = (1/2)y </span>
<span>Multiply both sides by 2... </span>
<span>2x^2 + 16x + 34 = y </span>
<span>...which is equal to equation D.</span>
Answer: Yes
Step-by-step explanation:
Using the vertical line test, we draw a bunch of lines that go up and down. We can see there is no point where a vertical line has 2 intersections.
Answer:
y=-2/3x+3
Step-by-step explanation:
(m)slope :rise over run
(b)y-intercept :where the line crosses the y axis
slope intercept for y=mx+b
The Given Triangle PMO is a Right Angled Triangle with m∠M = 90°
Given m∠P = 40°
We know that : Sum of Angles in a Triangle = 180°
⇒ m∠P + m∠M + m∠O = 180°
⇒ 40° + 90° + m∠O = 180°
⇒ 130° + m∠O = 180°
⇒ m∠O = 180° - 130°
⇒ m∠O = 50°
We can notice that m∠O and m∠1 form a Linear Pair (180°)
⇒ m∠O + m∠1 = 180°
⇒ 50° + m∠1 = 180°
⇒ m∠1 = 180° - 50°
⇒ m∠1 = 130°
Last Option is the Answer
