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Mariana [72]
3 years ago
12

Find the solution to the system of equations using substitution. 3x = 8 3x + y = 15

Mathematics
1 answer:
Tju [1.3M]3 years ago
7 0

Step-by-step explanation:

Step 1: Substitute 8 in the equation.

Step 2: Minus 8 from 15.

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find the least perfect square that is exactly divisible by each of the numbers 5 , 18 , 25 and 27 . ​
Dimas [21]
<h3>☂︎ Answer :- </h3>

  • 8100
<h3>☂︎ Solution :- </h3>

  • LCM of 5 , 18 , 25 and 27 = 2 × 3³ × 5²
  • 2 and 3 have odd powers . To get a perfect square, we need to make the powers of 2 and 3 even . The powers of 5 is already even .

In other words , the LCM of 5 , 18 , 25 and 27 can be made a perfect square if it is multiplied by 2 × 3 .

The least perfect square greater that the LCM ,

☞︎︎︎ 2 × 3³ × 5² × 2 × 3

☞︎︎︎ 2² × 3⁴ × 5²

☞︎︎︎ 4 × 81 × 85

☞︎︎︎ 100 × 81

☞︎︎︎ 8100

8100 is the least perfect square which is exactly divisible by each of the numbers 5 , 18 , 25 , 27 .

7 0
2 years ago
Answer asap ty.!<br><br> Thanks
Alex

Answer:

x=0

Step-by-step explanation:

5-9+3x = -10+6

-4+3x = -4

+4 .       +4 (Both sides)

3x = 0

/3    /3 . (divide both sides by 3)

x=0

3 0
3 years ago
Rebecca has $3.10 in her piggy bank and it contains only quarters and nickels. She has a total of 24 coins in her bank. How many
Nitella [24]

Answer:

15 dimes, 7 quarters, 2 nickels

5 0
3 years ago
Find the solution set for the given inequality if the replacement set is {1, 2, 3, 4, 5, 6).
nordsb [41]

4  \leqslant x   \leqslant  \infty

5 0
3 years ago
Can someone help me please​
d1i1m1o1n [39]

Answer:

a. 1200          f. 900

b. 600           g. 5700

c. 900           h. 4800

d. 300           i. 8300

e. 800           j. 8500

Step-by-step explanation:

First of all, you need to compute the sums. I find a calculator handy for this.

To round to hundreds, you can examine the digit in the next place to the right of the hundreds place. That digit in the tens place needs to be compared to 5. If it is 5 or greater, add 1 to the digit in the hundreds place. After you have done that, set the digits to the right of the hundreds place to zero.

__

Alternatively, you can add 1/2 of 100 to the sum, then set the digits to the right of the 100s place to zero. (Adding 50 will only change the 100's place digit if the 10's place digit is 5 or more.) This method doesn't require you do any thinking about the size of the digit; it is purely mechanical.

The sums and their rounded values are ...

a. 1221 ⇒ 1200

b. 568 ⇒ 600

c. 931 ⇒ 900

d. 347 ⇒ 300

e. 798 ⇒ 800

f. 911 ⇒ 900

g. 5681 ⇒ 5700

h. 4766 ⇒ 4800

i. 8328 ⇒ 8300

j. 8507 ⇒ 8500

8 0
4 years ago
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