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irakobra [83]
3 years ago
5

What is the inverse function of y = (x-4)^2 - 2​

Mathematics
1 answer:
salantis [7]3 years ago
4 0

Answer:

Step-by-step explanation:

x = (y-4)^2 - 2

square root of x = y - 4 - 2

square root of x = y - 6

(square root of x) - 6 = y

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4 years ago
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zepelin [54]

Answer:

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Step-by-step explanation:

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\sqrt{(x_{2}-x_{1} )^{2}+(y_{2}-y_{1})^{2}}\\Taking\ center\ as\ point\ 1\ and\ the\ other\ point\ as\ point\ 2\\d=\sqrt{(-3-5)^{2}+(2-(-4))^{2}}\\d=\sqrt{(-8)^{2}+(2+4)^{2}}\\d=\sqrt{(-8)^{2}+(6)^{2}}\\\\d=\sqrt{64+36}\\d=\sqrt{100} \\ d=10\\So\ the\ radius\ is\ 10

The standard form of equation of circle is:

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