What is the inverse function of y = (x-4)^2 - 2
1 answer:
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-x + 2y = 10
6y = -12x + 1
6y = -12x + 1
6 6
y = -2x + ¹/₆
-x + 2y = 10
-x + 2(-2x + ¹/₆) = 10
-x + 2(-2x) + 2(¹/₆) = 10
-x - 4x + ¹/₃ = 10
-5x + ¹/₃ = 10
- ¹/₃ - ¹/₃
-5x = 9²/₃
-5 -5
x = -1¹⁴/₁₅
y = -2x + ¹/₆
y = -2(-1¹⁴/₁₅) + ¹/₆
y = 3¹³/₁₅ + ¹/₆
y = 4¹/₃₀
(x, y) = (-1¹⁴/₁₅, 4¹/₃₀)
It is intersecting, making the answer equal to C.
6y = -12x + 1
6y = -12x + 1
6 6
y = -2x + ¹/₆
-x + 2y = 10
-x + 2(-2x + ¹/₆) = 10
-x + 2(-2x) + 2(¹/₆) = 10
-x - 4x + ¹/₃ = 10
-5x + ¹/₃ = 10
- ¹/₃ - ¹/₃
-5x = 9²/₃
-5 -5
x = -1¹⁴/₁₅
y = -2x + ¹/₆
y = -2(-1¹⁴/₁₅) + ¹/₆
y = 3¹³/₁₅ + ¹/₆
y = 4¹/₃₀
(x, y) = (-1¹⁴/₁₅, 4¹/₃₀)
It is intersecting, making the answer equal to C.
Answer:
m∠2 = 140°
Step-by-step explanation:
m∠1 = m∠3, since they're vertical angles.
Solve for x:
Plug in 6 for x for either m∠1 or m∠3. Doesn't matter since they're equal.
m∠1 = (2(6) + 28)°
m∠1 = (12 + 28)°
m∠1 = 40°
Now that we know m∠1, we can now solve for m∠2.
m∠1 + m∠2 = 180°
40° + m∠2 = 180°
m∠2 = 140°