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3 years ago

Due TONIGHT PLEASE DO!

Mathematics

1 answer:

Yanka [14]3 years ago

5 0

Answer:

50, 573, 57, R, 73

Step-by-step explanation:

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For what value of a does (1/9)^a+1 = 81^a+1 • 27^2-a

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Step-by-step explanation:

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Joe has 37 coins consisting of nickels, dimes, and quarters. There are four more nickels than dimes and two more quarters than n

astraxan [27]

Answer:

Step-by-step explanation:

Let n, d, q represent the numbers of nickels, dimes, and quarters. The problem statement tells us ...

n +d +q = 37

n = d +4

q = n +2

___

Rearranging the second equation gives ...

d = n -4

Substituting that into the first, we get ...

n + (n -4) +q = 37

2n +q = 41 . . . . . . . add 4 and simplify

Rearranging the third original equation gives ...

n = q -2

Substituting into the equation we just made, we get ...

2(q -2) +q = 41

3q = 45 . . . . . . . . add 4 and simplify

q = 15 . . . . . . . . . divide by 3

Joe has 15 quarters.

_____

<em>Check</em>

The number of nickels is 2 fewer, so is 13. The number of dimes is 4 fewer than that, so is 9. The total number of coins is 15 + 13 + 9 = 37, as required.

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3 years ago

The manager of a grocery store has taken a random sample of 100 customers. The average length of time it took these 100 customer

AlladinOne [14]

Answer:

$4-2.326\frac{1}{\sqrt{100}}=3.767$

$4+2.326\frac{1}{\sqrt{100}}=4.233$

So on this case the 98% confidence interval would be given by (3.767;4.233)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=4$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=1$ represent the population standard deviation

n=100 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.01,0,1)".And we see that $z_{\alpha/2}=2.326$

Now we have everything in order to replace into formula (1):

$4-2.326\frac{1}{\sqrt{100}}=3.767$

$4+2.326\frac{1}{\sqrt{100}}=4.233$

So on this case the 98% confidence interval would be given by (3.767;4.233)

4 0

3 years ago