All categories

3 years ago

Due TONIGHT PLEASE DO!

Mathematics

1 answer:

Yanka [14]3 years ago

5 0

Answer:

50, 573, 57, R, 73

Step-by-step explanation:

You might be interested in

Prove: If C⊂A and D⊂B then D−A⊂B−C

nalin [4]

Let $x\in D\setminus A$ , so that $x\in D$ but $x\not\in A$ . Since $D\subset B$ , it follows that $x\in B$ , and since $C\subset A$ , it follows that $x\not\in C$ , which means $x\in B\setminus C$ .

3 0

2 years ago

Please help the picture is

asambeis [7]

The walls are vertical so the angle opposite X would be a right angle which is 90 degrees.

X would be 180 - 90 - 35 = 55 degrees

X and 2y - 5 are complementary angles which add together to equal 90:

2y - 5 + 55 = 90

Simplify:

2y +50 = 90

Subtract 50 from both sides:

2y = 40

Divide both sides by 2:

y = 20

7 0

3 years ago

Read 2 more answers

Please help

MakcuM [25]

Hello there!

To find this, we must simplify this equation.

first, let's simplify the right side

-1 * x = -x

-1 * 5 = -5

Now, we have: y -3 = -x -5

Now we must add + 3 to each side to get rif of the negative three

now we have y = -x - 2

So, your answer is B.) y= -1x - 2

I hope my answer was of assistance!

~ Fire

7 0

3 years ago

Read 2 more answers

Quinton bought x number of shares for p dollars and paid a 0.5% commission. He sold the stock for y dollars and paid a flat fee

Ksju [112]

Answer:

$y-(0.05xp+7)$

Step-by-step explanation:-

As per the statement:

Quinton bought x number of shares for p dollars and paid a 0.5% commission

⇒ $0.05xp$

It is also given that: He sold the stock for y dollars and paid a flat fee of $7.

⇒ $y-7$

then;

Net proceeds is given as:

$y-7-0.05xp = y-(0.05xp+7)$

Therefore, Quinton's net proceeds algebraically is $y-(0.05xp+7)$

4 0

3 years ago

A pendant is formed using a cylinder and cone. Once assembled, as shown below, the pendant is painted. How many square millimete

solmaris [256]

Surface area of cylinder is given by area of circle + area of the rectangle that curved around the cylinder

Area of the base of the cylinder = $\pi r^{2} = 8^{2} \pi =64 \pi$
Area of the cylinder 'wall' = width × length = $12$ × $2r \pi$ = $12$ × $16 \pi$ = $192 \pi$

Note that the wall of the cylinder is in the shape of a rectangle. The width of the rectangle is the height of the cylinder. The length of the rectangle is the circumference of the circle base.

Surface area of cone is given by $\pirl$ where $l$ is the slanted height of the cone

SA of cone = $\pi (8)(10)=80 \pi$

Hence total painted surface area is $80 \pi +192 \pi +64 \pi =336 \pi$

3 0

3 years ago

Read 2 more answers