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Lesechka [4]
3 years ago
15

Simplify the expression. (16 − 9)^11 divided by [(3 + 4)^2]4

Mathematics
1 answer:
densk [106]3 years ago
8 0
Do 16-9 which equals 7, then (7)^11=77   1.=77
 
this one add 3+4 which equals 7 then do 7^2= 49 then 4x49=196   2.=196
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Any help appreciate :)
LiRa [457]

B makes the most sense. Try it out and let me know!!

3 0
3 years ago
Read 2 more answers
WILL GIVE 12 POINTS!!! PLEASE HELP MEEEE!!!A pair of equations is shown below. x + y = 5 y = one half x + 2 If the two equations
vfiekz [6]

Answer:

(2,3)

Step-by-step explanation:

x + y = 5:

2 + 3 = 5

y = 1/2x + 2:

3 = 1 + 2

3 0
4 years ago
Read 2 more answers
Let X be the number of accidents per week at the Hillsborough Street roundabout by the NCSU Bell Tower. Assume X varies with mea
Eduardwww [97]

Answer:

1) 0.1587 = 15.15% probability that x is less than 2

2) 7.64% probability that there are fewer than 100 accidents at the roundabout in a year

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the Central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 2.2, \sigma = 1.4

1)

Here we have \mu = 2.2, s = \frac{1.4}{\sqrt{52}} = 0.194

What is the probability that x is less than 2?

This is the pvalue of Z when X = 2.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{2 - 2.2}{0.194}

Z = -1.03

Z = -1.03 has a pvalue of 0.1515

0.1587 = 15.15% probability that x is less than 2

2)

100/52 = 1.9231

This is the pvalue of Z when X = 1.9231

Z = \frac{X - \mu}{s}

Z = \frac{1.9231 - 2.2}{0.194}

Z = -1.43

Z = -1.43 has a pvalue of 0.0764

7.64% probability that there are fewer than 100 accidents at the roundabout in a year

6 0
3 years ago
How many points are needed to determine a straight line?
GuDViN [60]

Answer:

2

Step-by-step explanation:

You only need two points to create a line...

8 0
3 years ago
Find the distance and midpoint for A(0,1) and B(2,6)
padilas [110]
I think the answer is (3, 6)
6 0
3 years ago
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