The complete question is :
Question: What is the coefficient in the expression 10x²-7?
The coefficient in the expression 
is 10
<h3>What is Coefficient?</h3>
A numerical or constant quantity placed before and multiplying the variable in an algebraic expression.
According to the question,
The expression given is
The variable given is x
We need to find the coefficient in the expression.
In the given expression x is the variable and the number before the x is coefficient which is 10 .
Hence the coefficient in the expression is 10.
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Answer: C. (-3, 9)
Step-by-step explanation:
Given
2|x-3|=12
Divide both sides by 2
2|x-3|/2=12/2
|x-3|=6
Take of absolute value sign (REMEMBER need to take into consideration of two conditions)
x-3=±6
1)x-3=6
x=9
2)x-3=-6
x=-3
**NOTE**: need to check each solution whether or not they are suitable
Hope this helps!! :)
Please let me know if you have any questions
*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*
(21)
Area of a Regular Hexagon: 
square units
(22)
Similar to (21)
Area = 
square units
(23)
For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:
Hence, area of the hexagon will be: 
square units
(24)
Given is the inradius of an equilateral triangle.
Substituting the value of inradius and calculating the length of the side of the equilateral triangle:
Side = 16 units
Area of equilateral triangle = 
square units
.725 multiplied by 4500=362.5
750+3262.5=4012.5
We set up a proportion: 80/?= 32/100
Cross multiply: 32*?= 80*100
⇒ ?= 80*100/32= 250
80 is 32% of 250.
