Answer:
one solution with a y value of 5
Step-by-step explanation:
/| x+y-4 = 0| x-y-6 = 0
We try to solve the equation: x+y-4 = 0
x+y-4 = 0 // - x-4
y = -(x-4)
y = 4-x
We insert the solution into one of the initial equations of our system of equations
We get a system of equations:
/| x+x-6-4 = 0| y = 4-x
2*x-10 = 0 // + 10
2*x = 10 // : 2
x = 10/2
x = 5
We insert the solution into one of the initial equations of our system of equations
For y = 4-x:
y = 4-5
y = -1
We get a system of equations:
/| y = -1| x = 5
Answer:
c = bx/(x+1)
Step-by-step explanation:
Add cx to get c-terms together, and divide by the coefficient of c.
bx = cx + c
bx = c(x +1) . . . . factor out c
bx/(x +1) = c
Note that fiona cannot sell decimal number of cupcakes or muffins. That's why the options A and D are false.
Consider all remaining options:
B. 40 cupcakes and 80 muffins will cost $(40·3+80·2)=$(120+160)=$280, but Fiona Follies sold at least $300 worth of cupcakes and muffins. Thus, this option is false.
C. 60 cupcakes and 70 muffins will cost $(60·3+70·2)=$(180+140)=$320. Now consider expenses. $(60·0.75+70·0.5)=$(45+35)=$80. This option is true.
E. 80 cupcakes and 80 muffins will cost $(80·3+80·2)=$(240+160)=$400. Now consider expenses. $(80·0.75+80·0.5)=$(60+40)=$100 (exactly $100). This option is true.
Answer: correct options are C and E.
To <span>transform the quadratic equation into the equation form (x + p)2 = q we shall proceed as follows:
3+x-3x^2=9
putting like terms together we have:
-3x^2+x=6
dividing through by -3 we get:
x^2-x/3=-2
but
c=(b/2a)^2
c=(-1/6)^2=1/36
thus the expression will be:
x^2-x/3+1/36=-2+1/36
1/36(6x-1)</span>²=-71/36
the answer is:
1/36(6x-1)²=-71/36
Answer:
Step-by-step explanation:
Slope-intercept form means
where m is given its the slope which is 
and we have the coordinates x and y which is (4, -5) and we need to find the value of c which is the y-intercept so we insert all these values into the equation so ,
now we know the value of slope which is given and we found the value of which is 1 so we put these values into our original slope-intercept form equation
