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Ivanshal [37]
3 years ago
15

What is six data type used in MS Access ​

Computers and Technology
1 answer:
Alika [10]3 years ago
4 0
Alphanumeric data, date/time, Numeric data, Currency, Lookup Wizard, Attachment.

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What are Boolean​ connectors? A. sites that connect you to more information on your topic B. databases that link your topic to a
Gala2k [10]

A,B,C AND D.  All depend on end user uses.

A. sites that connect you to more information on your topic

B. databases that link your topic to available sources

C. indexes on connective materials

D. shortcuts to help you narrow the search field

<u>Explanation:</u>

Boolean connectors are nothing but Boolean operators such as AND, OR, NOT, XOR,IMP, ISNOT , “=”, “>=”, “<>”,”<=” extra.

It all depends up how the end user uses in the programming languages. Normally if Boolean connector returns true value, instruction or set of instruction are used to execute for next core of action in the programming language.

Mostly in any programming language relation operators such as “=”, “>=”,”<=”,” <>” extra with his combination add on logical operators are used such as “And”, “OR” and “NOT” extra.

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3 years ago
Flash drive DVD and hard drive are all examples of
oee [108]

Answer:

flash drive DVD and hard drive are all examples of storage device

8 0
3 years ago
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A person gets 13 cards of a deck. Let us call for simplicity the types of cards by 1,2,3,4. In How many ways can we choose 13 ca
natima [27]

Answer:

There are 5,598,527,220 ways to choose <em>5</em> cards of type 1, <em>4 </em>cards<em> </em>of type 2, <em>2</em> cards of type 3 and <em>2</em> cards of type 4 from a set of 13 cards.

Explanation:

The <em>crucial point</em> of this problem is to understand the possible ways of choosing any type of card from the 13-card deck.

This is a problem of <em>combination</em> since the order of choosing them does not matter here, that is, the important fact is the number of cards of type 1, 2, 3 or 4 we can get, no matter the order that they appear after choosing them.

So, the question for each type of card that we need to answer here is, how many ways are there of choosing 5 cards of type 1, 4 cards of type 2, 2 cards of type 3 and 2 are of type 4 from the deck of 13 cards?

The mathematical formula for <em>combinations</em> is \\ \frac{n!}{(n-k)!k!}, where <em>n</em> is the total of elements available and <em>k </em>is the size of a selection of <em>k</em> elements  from which we can choose from the total <em>n</em>.

Then,

Choosing 5 cards of type 1 from a 13-card deck:

\frac{n!}{(n-k)!k!} = \frac{13!}{(13-5)!5!} = \frac{13*12*11*10*9*8!}{8!*5!} = \frac{13*12*11*10*9}{5*4*3*2*1} = 1,287, since \\ \frac{8!}{8!} = 1.

Choosing 4 cards of type 2 from a 13-card deck:

\\ \frac{n!}{(n-k)!k!} = \frac{13!}{(13-4)!4!} = \frac{13*12*11*10*9!}{9!4!} = \frac{13*12*11*10}{4!}= 715, since \\ \frac{9!}{9!} = 1.

Choosing 2 cards of type 3 from a 13-card deck:

\\ \frac{n!}{(n-k)!k!} =\frac{13!}{(13-2)!2!} = \frac{13*12*11!}{11!2!} = \frac{13*12}{2!} = 78, since \\ \frac{11!}{11!}=1.

Choosing 2 cards of type 4 from a 13-card deck:

It is the same answer of the previous result, since

\\ \frac{n!}{(n-k)!k!} = \frac{13!}{(13-2)!2!} = 78.

We still need to make use of the <em>Multiplication Principle</em> to get the final result, that is, the ways of having 5 cards of type 1, 4 cards of type 2, 2 cards of type 3 and 2 cards of type 4 is the multiplication of each case already obtained.

So, the answer about how many ways can we choose 13 cards so that there are 5 of type 1, there are 4 of type 2, there are 2 of type 3 and there are 2 of type 4 is:

1287 * 715 * 78 * 78 = 5,598,527,220 ways of doing that (or almost 6 thousand million ways).

In other words, there are 1287 ways of choosing 5 cards of type 1 from a set of 13 cards, 715 ways of choosing 4 cards of type 2 from a set of 13 cards and 78 ways of choosing 2 cards of type 3 and 2 cards of type 4, respectively, but having all these events at once is the <em>multiplication</em> of all them.

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Can my cell phone provider keep track of my internet history?
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who likes tom holland as spiderman and his web shooter tippets when he swings off buildings in new york city midtown, Forest Hil
S_A_V [24]

Answer:

YESSSS!!!!

Explanation:

5 0
3 years ago
Read 2 more answers
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