(3x^5y)^2=
3^2=9
(x^5)^2=x^10
y^2=y^2
(3x^5y)^2=9x^10y^2
9x^10y^2(4x^3y^5)=
9*4=36
x^10*x^3=x^13
y^2*y^5=y^7
9x^19y^2(4x^3y^5)= 36x^13y^7
Final answer: B
Answer:
The mean blood cholesterol level for the sample is 184mg/dl
Step-by-step explanation:
Hello!
When you construct any confidence interval for the mean, the general structure is "estimator±margin of error"
For example under a Z-distribution the formula is
X[bar]±
*(σ/√n)
So you subtract or add "
*(σ/√n)" to the sample mean. In other words, this type of confidence interval is centered on the sample mean.
If the interval is already calculated, you just have to add both limits and divide by two to get the sample mean.
[166mg/dl;202mg/dl]
sample mean: x[bar]= (166+202) = 184mg/dl
2
I hope you have a SUPER day!
Answer:
A. x+30
B. x+35
Step-by-step explanation:
A. Daniel
Since "Daniel is 30 cm taller than Katie" and "Katie's height is x cm", the expression will be x+30
B. Juli (sorry I can't type the full name due to Brainly system)
Since "Juli is 5 cm taller than Daniel" and Daniel is (x+30) cm, the expression will be (x+30)+5=x+35
The energy is compared based on the information given below.
<h3>How to illustrate the energy?</h3>
Energy released by burning 1 kilogram of element A = EA = 5.1 * (10)8
Energy released by fission of hydrogen in 1 kilogram of element B = EB = 1.3 * (10)10
Therefore,
Ratio = EB / EA = 1.3 * (10)10 / 5.1 * (10)8 = 25
Thus, the fission of 1 kg of element B releases 25 times as much energy as burning 1 kilogram of element A.
Learn more about energy on:
brainly.com/question/13881533
#SPJ1
<u>The other part of the question:</u>
Energy released by burning 1 kilogram of element A = 5.1 times 10 Superscript 8
Energy released by the fission of hydrogen in 1 kilogram of element B = 1.3 times 10 Superscript 10