Answer:
24.2(to the nearest tenth)
Step-by-step explanation:
The question is ungrouped data type
standard deviation =√ [∑ (x-μ)² / n]
mean (μ)=∑x/n
=
=33.3
x-μ for data 5, 5, 6, 12, 13, 26, 37, 49, 51, 56, 56, 84 will be
-28.3, -28.3, -27.3, -21.3, -7.3, 3.7, 15.7,17.7, 22.7,22.7,50.7
(x-μ)² will be 800.89, 800.89,745.29,453.69,53.29,13.69,246.49,313.29,515.29,515.29,2570.49
∑ (x-μ)² will be = 7028.59
standard deviation = √(7028.59 / 12)
=24.2
Answer:
a) , b)
, c)
, d)
Step-by-step explanation:
a) The spring constant is calculated by using this expression:
b) The work needed to compress the spring from its initial position is:
c) The work needed to stretch the spring is:
d) The work need to stretch the spring is:
Answer:
a) 8π
b) 8/3 π
c) 32/5 π
d) 176/15 π
Step-by-step explanation:
Given lines : y = √x, y = 2, x = 0.
<u>a) The x-axis </u>
using the shell method
y = √x = , x = y^2
h = y^2 , p = y
vol = ( 2π )
=
∴ Vol = 8π
<u>b) The line y = 2 ( using the shell method )</u>
p = 2 - y
h = y^2
vol = ( 2π )
=
= ( 2π ) * [ 2/3 * y^3 - y^4 / 4 ] ²₀
∴ Vol = 8/3 π
<u>c) The y-axis ( using shell method )</u>
h = 2-y = h = 2 - √x
p = x
vol =
=
= ( 2π ) [x^2 - 2/5*x^5/2 ]⁴₀
vol = ( 2π ) ( 16/5 ) = 32/5 π
<u>d) The line x = -1 (using shell method )</u>
p = 1 + x
h = 2√x
vol =
Hence vol = 176/15 π
attached below is the graphical representation of P and h
