It's 82 degrees. Subtract your minor arc (98) by 360 to get your major arc, which is 262. Then, subtract 98 (minor arc) from 262 (major arc), which gives you 164. Finally, divide 164 by 2 to get angle ABC.
Answer:
96 ft^2.
Step-by-step explanation:
Area of shaded region = area of the original rectangle - area of the one removed
= 8 * 16 - 8*4
= 128 - 32
= 96
Have you heard the expressions "shooting fish in a barrel" or
"taking candy from a baby" ?
I've decided to take your points and try not to feel guilty about it.
A). That's it ! That's the equation, for ANY basketball on Earth.
You wrote it right there in your question.
In that equation that you wrote, the ' r ' is the initial velocity.
You said that Adam tossed it straight up, and it was going 10 meters per second
when it left his hand.
So ' r ' in the equation is +10.
The equation is:
<em>d = 10t - 5t² </em> .
It tells you how high the ball is above its tossing height after any number of seconds.
The ' t ' in the equation is the number of seconds. Any letter could have been used,
but ' t ' was cleverly selected because it stands for 'time'.
B). You want to know where it is after 0.5 second ? All you have to do is put '0.5'
into the equation wherever there's a ' t '. Do you really need somebody to do that
for you ?
Well, OK. You're being so overly generous with your points . . .
Distance = 10 t - 5 t²
Distance = 10 (0.5) - 5 (0.5)²
Distance = 5 - 5(0.25)
Distance = 5 - 1.25
<em>Distance = 3.75 meters </em>
<u>positive</u> 3.75 means <u>above</u> Adam's hand.
A thinking exercise:
-- He tossed the ball upwards at 10 meters per second.
-- Why is it not 5 meters above his hands after 0.5 second?
