What is the shape of f(x)

Mathematics

1 answer:

KonstantinChe [14]3 years ago

8 0

f(x) is concave down on an interval I if all of the tangents to the curve on I are above the graph of f(x)

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About 15% of the population of a large country is allergic to pollenallergic to pollen. if two people are randomly selected, w

zubka84 [21]

P(allergic) = 0.15

P(both are allergic to pollen) = (0.15)² = 0.0225 (you can use the binomial probability also)

Q(NOT allergic to pollen) = 1 - 0.0225 = 0.9775
Binomial probability

Probability of NEITHER is allergic
ⁿCₓ(p)ˣ(q)ⁿ⁻ˣ
²C₀(0.15)⁰(0.9775)² = 0.9555

P(at LEAST ONE is allergic) = 1- 0.9555 = 0.0444

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4 years ago

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I'm not sure if I am right and just want to make sure I got the right answer

djyliett [7]

Answer:

The answer is 9

Step-by-step explanation:

The answer is 9

7 0

3 years ago

Find 2 common angles that sum to (17pi/12) 2. Evaluate tan(17pi/12) using the sum identity for tangent.

Dmitry [639]

Note that
$\frac{17 \pi }{12} = \frac{3 \pi }{12} + \frac{14 \pi }{12} = \frac{ \pi }{4} + \frac{7 \pi }{6}$

Note that
$x= \frac{ \pi }{4}:\,\, sin(x) =cos(x)= \frac{1}{ \sqrt{2} },\,tan(x)=1\\x= \frac{7 \pi }{6} :\,\,sin(x)=- \frac{1}{2} ,\,\,cos(x)=- \frac{ \sqrt{3} }{2} ,\,\,tan(x)= \frac{1}{ \sqrt{3} }$

Use the identity
$tan(x+y)= \frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

Therefore
$tan( \frac{17 \pi }{12} )= \frac{1+ \frac{1}{ \sqrt{3} } }{1- \frac{1}{ \sqrt{3} } } = \frac{ \sqrt{3}+1 }{ \sqrt{3}-1} = \frac{( \sqrt{3}+1 )^{2}}{( \sqrt{3}-1 )( \sqrt{3}+1 )} = \frac{3+1+2 \sqrt{3}}{3-1} =2+ \sqrt{3}$

Answer: 2 + √3

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3 years ago

A triangle in the coordinate plane has coordinates of (2,3), (-4,-5), and (-2,4). It is translated 3 units down. What are it’s n

Sophie [7]

Answer:

see below

Step-by-step explanation:

translated 3 units down whic means -3 on the y

hence T1 (2,0), T2 (-4,-8), T3 (-2, 1)

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3 years ago

Which expression is equivalent to this expression?

Lyrx [107]

Answer:

a-4b

Step-by-step explanation:

you combine like terms, (-6b)+2b=-4

4a-3a=1a or just a

then you get your awsner a-4

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3 years ago