Answer:
minimum of 13 chairs must be sold to reach a target of $6500
and a max of 20 chairs can be solved.
Step-by-step explanation:
Given that:
Price of chair = $150
Price of table = $400
Let the number of chairs be denoted by c and tables by t,
According to given condition:
t + c = 30 ----------- eq1
t(150) + c(400) = 6500 ------ eq2
Given that:
10 tables were sold so:
t = 10
Putting in eq1
c = 20 (max)
As the minimum target is $6500 so from eq2
10(150) + 400c = 6500
400c = 6500 - 1500
400c = 5000
c = 5000/400
c = 12.5
by rounding off
c = 13
So a minimum of 13 chairs must be sold to reach a target of $6500
i hope it will help you!
If degree of variable is one then eq. is linear
so given is linear.
L=(8/3)W = 24 ft. Solving for W, we mult. both sides of this eqn by (3/8), obtaining
W = (3/8)(24 ft) = 9 ft (answer)
I’m 15 so the answer is number 1
