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Otrada [13]
3 years ago
15

The two triangles shown have the same perimeters. What is the perimeter of each triangle

Mathematics
1 answer:
Shkiper50 [21]3 years ago
7 0

Answer:

28 units

Step-by-step explanation:

Since the perimeter of both triangles is same,

the sum of all sides of first triangle = sum of all sides of second triangle

or, 6x + 3 + 2x + 4x = 5x + 5x + 3x + 2

or, 12x + 4 = 13x + 2

or, 4-2 = 13x - 12x

or, 2 = x

Now,

Putting the value of x in the perimeter of first triangle,

12x + 4= 12* 2+ 4

= 28 units

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Select the correct answer
motikmotik

Answer:

4

Step-by-step explanation:

80%=4/5

4/5 of 20 is 4

They lose 4 matches.

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3 years ago
Which expression is equivalent to 512 in exponential form?
OleMash [197]

Answer:

a)2*2*2*2*2*2*2*2*2

Step-by-step explanation:

it wouldn't be done 2*9 but exactly how it is written like

2 by the power of 9

3 0
3 years ago
What is the error in the work?
N76 [4]

Answer:

you cannot subtract 12x² from -14x they are not "like" terms

Step-by-step explanation:

6 0
3 years ago
3. A rare species of aquatic insect was discovered in the Amazon rainforest. To protect the species, environmentalists declared
navik [9.2K]

The number of months until the insect population reaches 40 thousand is 14.29 months and the limiting factor on the insect population as time progresses is 250 thousands.

Given that population P(t) (in thousands) of insects in t months after being transplanted is P(t)=(50(1+0.05t))/(2+0.01t).

(a) Firstly, we will find the number of months until the insect population reaches 40 thousand by equating the given population expression with 40, we get

P(t)=40

(50(1+0.05t))/(2+0.01t)=40

Cross multiply both sides, we get

50(1+0.05t)=40(2+0.01t)

Apply the distributive property a(b+c)=ab+ac, we get

50+2.5t=80+0.4t

Subtract 0.4t and 50 from both sides, we get

50+2.5t-0.4t-50=80+0.4t-0.4t-50

2.1t=30

Divide both sides with 2.1, we get

t=14.29 months

(b) Now, we will find the limiting factor on the insect population as time progresses by taking limit on both sides with t→∞, we get

\begin{aligned}\lim_{t \rightarrow \infty}P(t)&=\lim_{t \rightarrow \infty}\frac{50(1+0.05t)}{2+0.01t}\\ &=\lim_{t \rightarrow \infty}\frac{50(\frac{1}{t}+0.05)}{\frac{2}{t}+0.01}\\ &=50\times \frac{0.05}{0.01}\\ &=250\end

(c) Further, we will sketch the graph of the function using the window 0≤t≤700 and 0≤p(t)≤700 as shown in the figure.

Hence, when the population P(t) (in thousands) of insects in t months after being transplanted by P(t)=(50(1+0.05t))/(2+0.01t) then the number of months until the insect population reaches 40 thousand 14.29 months and the limiting factor on the insect population is 250 thousand and the graph is shown in the figure.

Learn more about limiting factor from here brainly.com/question/18415071.

#SPJ1

8 0
2 years ago
What is Mary biking speed in miles per hour
Trava [24]

Answer:20

Step-by-step explanation: This is answer is 20 because you have to divide 10 1/2 to get your answer .

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3 years ago
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