Answer:
f'(x) = -f(x) = 9xy² - 6x²y + 5x³
Step-by-step explanation:
f(x) = –9xy² + 6x²y – 5x³
additive inverse: f'(x) = -f(x) = 9xy² - 6x²y + 5x³
f(x) + f'(x) = f(x) -f(x) = (–9xy² + 6x²y – 5x³) + (9xy² - 6x²y + 5x³) = 0
Answer:
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Step-by-step explanation:
Y = mx + c
7= (-5)(-2)+ c
7= 10 +c
7-10=c
-3=c
Equation of the line: y = -5x-3
Sub in (a, 2)
2= - 5(a)-3
2+3= -5a
5= - 5a
1= - a
A = -1
