The answer is Luge. And I searched up your question and found the whole practice sheet with the answer key. Just put the question on google and you'll find it.
Hope this helps!
Yea they are cuz they have the same side and angle measurements
Answer:
Ok, so the answer is 3.5
Step-by-step explanation:
From what I could see it says walked for 14 around her block 4 times so your answer is 3.5 because if (Let's call her Patricia) Patricia walked around her block 4 times in 14 minutes, we have to find the unit rate, therefore we have to divide 14 by 4 as shown below
Thus your only viable solution is 3.5
Hope this Helps! Also, I would appreciate it if I could be rewarded with Brainliest, I work hard on these answers and I would enjoy it, you see my goal is to reach Genius status, as to provide many more helpful answers and help many more people. Even so, I hope that I have come of assistance to you!
He counted too far. 5 x 2 is 10. He counted up to 25 which is 5 x 5, past what he is looking for.
If points A, E and C are colinear, then they lie on the same line. The same statement you can say about points B, F and D.
1. Consider triangles AOC and BOD. In these triangles:
- AO≅OB (given);
- CO≅OD (given);
- ∠AOC≅∠BOD (as vertical angles).
Thus, ΔAOC≅ΔBOD by SAS Postulate (If any two corresponding sides and their included angle are the same in both triangles, then the triangles are congruent). Corresponding parts of congruent triangles are congruent, then
- AC≅BD;
- ∠ACO≅∠BDO;
- ∠CAO≅∠DBO.
Since angles ACO and BDO are alternate interior angles between lines AE and BF with transversal CD and these angles are congruent, then lines AE and BF are parallel.
This gives you that
2. Consider triangles ECO and FDO. In these triangles
- ∠CEO≅∠OFD (previous proof);
- CO≅OD (given);
- ∠ECO≅∠ODF (previous proof).
Therefore, ΔECO≅ΔFDO by AAS Postulate (if two angles and the non-included side one triangle are congruent to two angles and the non-included side of another triangle, then these two triangles are congruent). Then CE≅FD.
3. Note that
Since AC≅BD and CE≅DF, then AE=AC+CE=BD+DF=BF.
