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sweet-ann [11.9K]
3 years ago
13

F(x)=x^2-3x+2 find f(2)

Mathematics
2 answers:
Maru [420]3 years ago
7 0

Answer:

y=x^{2} -3x+2

Step-by-step explanation:

Give me Brainllest plz T-T

slega [8]3 years ago
5 0

Answer:

0

Step-by-step explanation:

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Find the area of a trapezoid whose height is 2 meters and whose bases are 6 meters and 10 meters
zhannawk [14.2K]

Answer:

16 m^2

Step-by-step explanation:

The area of a trapezoid is given by

A = 1/2 (b1+b2) *h

   = 1/2 ( 6+10) * 2

   = 16 m^2

3 0
3 years ago
Read 2 more answers
Help pls! 10 points!
Zarrin [17]
Do I have to do all of them?
8 0
3 years ago
5^5 over 5^8<br>simplify​
svetoff [14.1K]

Step-by-step explanation:

5⁵/5⁸

= 5^5-8

= 5^-3

or

(-5)×(-5)×(-5)

= -125

By the law

a^m÷ a^n = a^m-n

6 0
3 years ago
You get a bagel for
Reika [66]

Answer:

You will get $1.96 in change.

Step-by-step explanation:

Add up the cost of the purchase

$1.95 for the bagel + $1.09 for the juice = $3.04

Subtract this from $5

$5 - $3.04 = $1.96

If this answer is correct, please make me Brainliest!

7 0
3 years ago
According to a survey, the average American person watches TV for 3 hours per week. To test if the amount of TV in New York City
Neporo4naja [7]

Answer:

Test statistic (t-value) of this one-mean hypothesis test is -2.422.

Step-by-step explanation:

We are given that according to a survey, the average American person watches TV for 3 hours per week. She surveys 19 New Yorkers randomly and asks them about their amount of TV each week, on average. From the data, the sample mean time is 2.5 hours per week, and the sample standard deviation (s) is 0.9 hours.

We have to test if the amount of TV in New York City is less than the national average.

Let Null Hypothesis, H_0 : \mu \leq 3  {means that the amount of TV in New York City is less than the national average}

Alternate Hypothesis, H_1 : \mu > 3   {means that the amount of TV in New York City is more than the national average}

The test statistics that will be used here is One-sample t-test statistics;

        T.S. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean time = 2.5 hours per week

             s = sample standard deviation = 0.09 hours

             n = sample size = 19

So, <u>test statistics</u> = \frac{2.5 - 3}{\frac{0.9}{\sqrt{19} } } ~ t_1_8

                              = -2.422

Therefore, the test statistic (t-value) of this one-mean hypothesis test (with σ unknown) is -2.422.

8 0
4 years ago
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