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Tanzania [10]
3 years ago
14

How do I do this? (Will give Brainliest) (Instructions if you could please)

Mathematics
2 answers:
andrew11 [14]3 years ago
8 0

Answer:

C

Step-by-step explanation:

tekilochka [14]3 years ago
4 0
It’s C I just know it I solve it that’s why
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Help someone plzzzzzzz
mafiozo [28]
The answer to the problem is
y=1/2x
3 0
3 years ago
Read 2 more answers
A linear function is a function in which the dependent variable changes at a constant rate relative to the independent variable.
sveticcg [70]

Answer:Yes

No

no

Yes

Step-by-step explanation:

6 0
3 years ago
A video game that normally sells for $80 is on sale for $68. What is the percent of discount for the sale price?
Snezhnost [94]

Answer:

C

Step-by-step explanation:

68 - 80 / 80

= - 12 / 80

= - 3 / 20

= - 15%

4 0
3 years ago
How does the volume of a sphere with radius 2cm compare to the volume of a sphere with radius 1cm​
satela [25.4K]

if you take the radius of the first and second sphere you find that they are doubled there fore the volume changed at a rate of 2 squared because 2 is what the radius was multiplied by going from the second sphere to the first so you would square what the sphere was multiplied by there fore making your answer: the volume is compares with 2 squared

5 0
3 years ago
How do you do these two questions?
nignag [31]

Step-by-step explanation:

(a) ∫₋ₒₒ°° f(x) dx

We can split this into three integrals:

= ∫₋ₒₒ⁻¹ f(x) dx + ∫₋₁¹ f(x) dx + ∫₁°° f(x) dx

Since the function is even (symmetrical about the y-axis), we can further simplify this as:

= ∫₋₁¹ f(x) dx + 2 ∫₁°° f(x) dx

The first integral is finite, so it converges.

For the second integral, we can use comparison test.

g(x) = e^(-½ x) is greater than f(x) = e^(-½ x²) for all x greater than 1.

We can show that g(x) converges:

∫₁°° e^(-½ x) dx = -2 e^(-½ x) |₁°° = -2 e^(-∞) − -2 e^(-½) = 0 + 2e^(-½).

Therefore, the smaller function f(x) also converges.

(b) The width of the intervals is:

Δx = (3 − -3) / 6 = 1

Evaluating the function at the beginning and end of each interval:

f(-3) = e^(-9/2)

f(-2) = e^(-2)

f(-1) = e^(-1/2)

f(0) = 1

f(1) = e^(-1/2)

f(2) = e^(-2)

f(3) = e^(-9/2)

Apply Simpson's rule:

S = Δx/3 [f(-3) + 4f(-2) + 2f(-1) + 4f(0) + 2f(1) + 4f(2) + f(3)]

S ≈ 2.5103

5 0
3 years ago
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