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vitfil [10]
3 years ago
9

Help me solve this (pls show working)

Mathematics
1 answer:
maksim [4K]3 years ago
6 0

Answer:

The area of the polygon is 92.75 cm^2

Step-by-step explanation:

To find the area of the polygon, we simply add up the areas of the constituent triangles

At any point in time;

Area of a triangle = 1/2 * base * height

So we proceed as follows;

(1/2 * 12 * 4.5) + (1/2 * 12 * 5)

= 27 + 30 = 57 cm^2

There is a last triangle with 12 cm and 5 cm as the sides and we need the length of the hypotenuse

The length of the hypotenuse for that triangle will be 13 cm. This is because 5,12 and 13 are Pythagorean triple and they form the sides of a right-angled triangle

So for the last triangle, the area will be;

1/2 * 13 * 5.5 = 35.75 cm^2

So the total area is;

35.75 + 57 = 92.75 cm^2

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When an electric current passes through two resistors with resistance r1 and r2, connected in parallel, the combined resistance,
kondaur [170]

Answer:

a)

The combined resistance of a circuit consisting of two resistors in parallel is given by:

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where

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In order to see if the function is increasing in r1, we calculate the derivative with respect to r1: if the derivative if > 0, then the function is increasing.

The derivative of R with respect to r1 is:

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We notice that the derivative is a fraction of two squared terms: therefore, both factors are positive, so the derivative is always positive, and this means that R is an increasing function of r1.

b)

To solve this part, we use again the expression for R written in part a:

R=\frac{r_1 r_2}{r_1+r_2}

We start by noticing that there is a limit on the allowed values for r1: in fact, r1 must be strictly positive,

r_1>0

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0

From part a), we also said that the function is increasing versus r1 over the whole domain. This means that if we consider a certain interval

a ≤ r1 ≤ b

The maximum of the function (R) will occur at the maximum value of r1 in this interval: so, at

r_1=b

6 0
3 years ago
5
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This is called the Pythagorean theorem : a ² + b ² = c ². You can substitute any of the variable with any of the known numbers and then you all you have to do is isolate the variable. I hope that helps!!
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