Function 1 has a maximum at y = 1
Now we need to find the maximum of Function 2 by completing the square:
-x^2 + 2x - 3
= -(x^2 - 2x) - 3
= -(x - 1)^2 +1 - 3
= -(x - 1)^2 - 2
Therefor the turning point is at (1, -2) and the maximum is at y = -2
-2 < 1, therefor Function 1 has the larger maximum
the answer is
x=8y/3(1-8y)
y=3x/8(1+3x)
hope this helped l used cymath to solve this problem.
good day : )
Step-by-step explanation:
I cant show a number line so i'll do my best to explain how its graphed.
15) x - 1 < 15
add 1 to both sides:
x < 16
Because it is less than, rather than less than or equal to, it's graphed with an open circle (not filled in) on 16, and everything less than 16 highlighted
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16) 2(y + 1) - 2 ≥ 12
distribute the 2:
2y + 2 - 2 ≥ 12
combine like terms
2y ≥ 12
isolate y:
y ≥ 6
This one is greater than or equal to, so it's graphed with a closed circle (filled in) and everything above 6 highlighted
Answer:
6,048
Step-by-step explanation:
l=3w
3w + 3w + w +w =96
8w =96
w=12
l= 36
12×36×14 = 6,048
