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Vedmedyk [2.9K]
3 years ago
10

Help please What is 20000 x 0

Mathematics
2 answers:
Alecsey [184]3 years ago
8 0

Answer:

its 0

Step-by-step explanation:

posledela3 years ago
5 0

Answer:

0

Step-by-step explanation:

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Trella alcala deposited 1,950 in a new credit union savings account on the first of the quarter the principal earns 4.25 percent
mrs_skeptik [129]
Amount in compound interest = p(1 + r/t)^nt where p is the initial deposit, r = rate, t = number of compunding in a period and n = period.

Here, Amount after 6 months (0.5 year) = 1,950(1 + (4.25/100)/4)^(0.5 x 4) = 1,950(1 + 0.0425/4)^2 = 1,950(1 + 0.010625)^2 = 1,950(1.010625)^2 = 1,950(1.0213629) = $1,991.66

Compound interest = Amount - principal (initial deposit) = $1,991.66 - $1,950 = $41.66
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3 years ago
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Who needs free 50 points only two winners hurry up
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3 years ago
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Find the roots of h(t) = (139kt)^2 − 69t + 80
Sonbull [250]

Answer:

The positive value of k will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80, roots are those values of t so that h(t) = 0. That is:

19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0 (1)

Roots are determined analytically by the Quadratic Formula:

t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}

t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }

The smaller root is t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }, and the larger root is t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }.

h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80 has one real root when \frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0. Then, we solve the discriminant for k:

\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}

k \approx \pm 0.028

The positive value of k will result in exactly one real root is approximately 0.028.

7 0
3 years ago
Helppppppp pllzzzzzzz
torisob [31]
I can't answer this because I don't know what she was starting with
5 0
4 years ago
Need help with finding the area of this
dusya [7]
In the given figure, there are two right angled triangles.

Area of triangle = 1/2 × b × h

Area of shaded region = area of larger triangle - area of smaller triangle

= 1/2 × 15 × 18 - 1/2 × 8 × 9

= 135 - 36

= 99 ft^2

Thus, area of shaded region is 99 ft^2.

3 0
4 years ago
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