Please help!!!!! With steps/work shown

gayaneshka [121]

See attachment file below.
Answer: 11/3

Hope it helped!

6 0

4 years ago

Marisa bought three movies for $9.99 each into video games for $14.99 each the prices included tax she gave the cashier $70 how

Mrrafil [7]

Answer:

106.70 because you have to subtract 14.99 by 9.99 which is 106.00 and then add that to 70 and your answer is 106.70. by the way I am a kid and a fifth grader.

3 0

3 years ago

Please HELP

Phoenix [80]

Answer:

x=52 m1= 40 m2= 140

Step-by-step explanation:

x-12+x+88=180 since they are linear pair

2x+76=180 collect like terms

2x=180-76

2×÷2=104÷2

×=52

give me a heart and good rate please<3

6 0

3 years ago

AKS 18/19 A travel agent is arranging a private cruise. The agent can arrange for, at most, 40 people to go on the trip. The tri

zlopas [31]

Answer:

M + W <= 40

M >= 12

M >= 15

Total profit = $26 * M + $14 * W

Step-by-step explanation:

Let the number of men be denoted by M

number of women be denoted by W

Maximum no of people that can go one trip = 40

Therefore representing it mathematically we have

M + W <= 40 -------------- CONSTRAINT 1

Minimum number of men needed on trip = 12

Therefore representing it mathematically we have

M >= 12 CONSTRAINT 2

Minimum number of women needed on trip = 15

Therefore representing it mathematically we have

M >= 15 CONSTRAINT 3

profit on 1 man = $26

profit on M men = $26 * M

profit on 1 woman = $14

profit on M men = $14 * W

Total profit combining for men and women =

$26 * M + $14 * W -------------CONSTRAINT 4

___________________________________________

writing together all the constraint

M + W <= 40

M >= 12

M >= 15

Total profit = $26 * M + $14 * W

4 0

3 years ago

If a sequence c1,c2,c3,...has limit K then the sequence ec1,ec2,ec3,...has limit e^K. Use this fact together with l'Hopital's ru

aleksandrvk [35]

Answer:

Step-by-step explanation:

If a sequence c1,c2,c3,...has limit K then the sequence ec1,ec2,ec3,...has limit e^K. Use this fact together with l'Hopital's rule to compute the limit of the sequence given by

bn=(n)^(5.6/n).

a)

$L = \lim_{n \to \infty} b_n \\\\\\L= \lim_{n \to \infty} n^{\frac{5.6}{n} }$

Log on both sides

$In (L) = \lim_{n \to \infty} In (n)^{\frac{5.6}{n} }\\\\= \lim_{n \to \infty} \frac{5.6}{n} In(n)$

$=5.6 \lim_{n \to \infty} \frac{d}{dn} In(n)/\frac{d}{dn} (n)\\\\=5.6 \lim_{n \to \infty} \frac{1}{n} /1 \\\\=5.6 \lim_{n \to \infty} \frac{1}{n} \\\\=5.6 \times 0\\\\In(L) =0\\\\L=e^0\\\\L=1$

$\therefore \lim_{n \to \infty} (n)^{\frac{5.6}{n} =1$

5 0

3 years ago