Find a 101 of the sequence 5, 8, 11, ....
A. 302
B. 311
C. 305
D. 308
1 answer:
Answer:
305
Step-by-step explanation:
We are adding 3 each time
5+3 = 8
8+3 = 11
The formula for an arithmetic sequence is
an = a1+d(n-1) where a1 is the first term and d is the common difference
an = 5+3(n-1)
We want the 101 term
a101 = 5 +3(101-1)
= 5+3(100)
= 5+300
= 305
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Explanation:
Answer:
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Step-by-step explanation:
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Do a proportion
60/100= x/54
Cross multiply and divide
54 x 60= 3,240
3,240 divided by 100 is 32.4
Now subtract
54- 32.4= 21.6
Answer is $21.6
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I'll have to say the answer is
B and A