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2 years ago

Whats the solution

Mathematics

1 answer:

Sergio039 [100]2 years ago

5 0

Answer:

Step-by-step explanation:

To find the center and the radius, we need to put the equation in the (x-a)^2+(y-b)^2=r^2 [a is the x-coordinate, b is the y-coordinate, and r is the radius].

(x+6)^2+(y+7)^2 - 36 - 49 + 69 = 0

(x+6)^2+(y+7)^2 - 16 = 0

(x+6)^2+(y+7)^2 = 16

(x+6)^2+(y+7)^2 = 4^2

The center is (-6,-7) and the radius is 4.

Hope this helps!

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Vanessa's scale drawing of a volleyball court, shown below, is 3 inches long and 1 1/2 inches wide. How many square meters make

natima [27]

I took a test on this yesterday and all i know is the answer is either 81 117 or 162

6 0

3 years ago

An air traffic controller is tracking two planes.To start Plane A was at an altitude of 990 meters and plane B was at an altitud

soldi70 [24.7K]

The equation representing when the two planes would be at the same altitude is 9x=486

<h3>In terms of mathematics, what is an equation?</h3>

Equation: A declaration that two expressions with variables or integers are equal. In essence, equations are questions, and attempts to systematically identify the solutions to these questions have been the driving forces behind the creation of mathematics.

From (a) we get that: Altitude of Plane A = 990-18x

Altitude of Plane B = 1476-27x

make 890 - 18x = 1476-27x

-18x+27 x = 1476-890

9x=486

X= 54

so pass 54 seconds will the two plane at the same altitude.

To learn more about equations from given link

brainly.com/question/25678139

#SPJ9

8 0

11 months ago

The average amount of time that students use computers at a university computer center is 36 minutes with a standard deviation o

frosja888 [35]

Answer:

2119 students use the computer for more than 40 minutes. This number is higher than the threshold estabilished of 2000, so yes, the computer center should purchase the new computers.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 36, \sigma = 5$

The first step to solve this question is finding the proportion of students which use the computer more than 40 minutes, which is 1 subtracted by the pvalue of Z when X = 40. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{40 - 36}{5}$

$Z = 0.8$

$Z = 0.8$ has a pvalue of 0.7881.

1 - 0.7881 = 0.2119

So 21.19% of the students use the computer for longer than 40 minutes.

Out of 10000

0.2119*10000 = 2119

2119 students use the computer for more than 40 minutes. This number is higher than the threshold estabilished of 2000, so yes, the computer center should purchase the new computers.

8 0

2 years ago

Draw a diagram that shows 1/5 times 30 equals 6

MrMuchimi

Total number = 30

1/5 of 30 = 1/5 x 30 = 6

The attached figures show the total number of filled circles in five lines. Each line have “6” filled circles.

So 5 lines having 6 filled circles = 5 x 6 = 30

<span>Every line represents “1/5” of total amount “30”. Which proved that 1/5 of 30 is equal to 6. </span>

3 0

2 years ago

Read 2 more answers

ricardo purchased a bunk bed for his children fora sale price of $276.25. The sale price was 65% of the original price. Calculat

nikklg [1K]

Use the formula S=P-PD

S is sale price, original price is P, and PD is discounted percent,

276.25=P-P(.65), I turned the percent into a decimal.

276.25=P(1-.65)

276.25=P(.35)

Now cross multiply.

$\frac{276.26}{.35}=\frac{P(.35)}{.35}\\\\P=\frac{276.26}{.35}=789.31$

Hope this helps, now you know the answer and how to do it. Stay healthy and safe and HAVE A BLESSED AND WONDERFUL DAY! :-)

- Cutiepatutie ☺❀❤

6 0

2 years ago

Whats the solution ​

Whats the solution