Hi there!
To solve, we must use the following trig identity:
sin(u - v) = sin(u)cos(v) - sin(v)cos(u)
We can rewrite the left hand side of the equation as:
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Split the fraction:
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First fraction reduces to 1:

Simpify each with common arguments:

Answer:
* The mean (a measure of central tendency) weight value is the average of the weights of all pennies in the study.
* The standard deviation (a measure of variability or dispersion) describes the lowest and highest any individual penny weight can be. Subtracting 0.02g from the mean, you get the lowest penny weight in the group.
Step-by-step explanation:
Recall that a penny is a money unit. It is created/produced, just like any other commodity. As a matter of fact, almost all types of money or currency are manufactured; with different materials ranging from paper to solid metals.
A group of pennies made in a certain year are weighed. The variable of interest here is weight of a penny.
The mean weight of all selected pennies is approximately 2.5grams.
The standard deviation of this mean value is 0.02grams.
In this context,
* The mean (a measure of central tendency) weight value is the average of the weights of all pennies in the study.
* The standard deviation (a measure of variability or dispersion) describes the lowest and highest any individual penny weight can be. Subtracting 0.02g from the mean, you get the lowest penny weight in the group.
Likewise, adding 0.02g to the mean, you get the highest penny weight in the group.
Hence, the weight of each penny in this study, falls within
[2.48grams - 2.52grams]
Question 1 - the first choice is right
Question 2- the first choice also
Answer:
H
Step-by-step explanation:
Step 1 of 2: Subtract, sub-step b: Convert mixed number to improper fraction.
Convert mixed number to improper fraction
2 and 1 over 32
1
3
= ( 2 × 3 ) over 3
2 × 3
3
+ 1 over 3
1
3
= ( 6 + 1 ) over 3
6 + 1
3
= 7 over 3
7
3
Step 1 of 2: Subtract, sub-step c: Find common denominator.
Find common denominator
32 over 9
32
9
− 7 over 3
7
3
= ( 32 × 1 ) over ( 9 × 1 )
32 × 1
9 × 1
− ( 7 × 3 ) over ( 3 × 3 )
7 × 3
3 × 3
= 32 over 9
32
9
− 21 over 9
21
9
9 is the least common multiple of denominators 9 and 3. Use it to convert to equivalent fractions with this common denominator.
Step 1 of 2: Subtract, sub-step d: Subtract.
Subtract
32 over 9
32
9
− 21 over 9
21
9
= ( 32 − 21 ) over 9
32 − 21
9
= 11 over 9
11
9
Step 1 of 2: Subtract.
Step 2 of 2: Simplify.
Simplify
11 over 9
11
9
= 1 and 2 over 91
2
9