Answer:
A) 34.13%
B) 15.87%
C) 95.44%
D) 97.72%
E) 49.87%
F) 0.13%
Step-by-step explanation:
To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:
P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)
= 0.5 - 0.1587 = 0.3413
It means that the PERCENT of scores that are between 90 and 100 is 34.13%
At the same way, we can calculated the percentages of B, C, D, E and F as:
B) Over 110

C) Between 80 and 120

D) less than 80

E) Between 70 and 100

F) More than 130

Answer:
-6
Step-by-step explanation:
4.8(x)+1.2(y)=2.4
9.6 + 1.2y = 2.4
subtract 9.6 from both sides
1.2y = - 7.2
divide by 1.2 on both sides
y = -6
I think this is your question right????
3.498947368421053 <- Exactly...
Evenly: Three times. It comes out to be 1425 with 237 left...
I hope this answers your question... Let me know if I didn't! <3
The answer would be 198/300. That simplified would be 33/50. If you want a percent, it would be 66%.
Answer:
True
Step-by-step explanation:
It is true because the graph of
passes through the point 
x = 16
y = 4
Substitute
4 = 16 - 12
4 = 4
Therefore, the answer is true.