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Aleks04 [339]
3 years ago
12

Let’s say A plant cell, normally diploid, completely screws up mitosis during metaphase and pulls full copies of all chromosomes

to one side duplicating the entire genome and all chromosomes. What “n” would this result in? Hint: another term for this is tetraploid.
Biology
1 answer:
andrezito [222]3 years ago
8 0

Answer:

4N

Explanation:

Mitosis is the process whereby a cell duplicates or produces another identical copy of itself. The mitotic process, which occurs in four main stages produces two daughter cells that are genetically identical to the parent cell. For example, a diploid organism (2n) will produce two daughter cells with 2n from mitosis.

However, in a case whereby a plant cell (A) screws up mitosis during metaphase and pulls full copies of all chromosomes to one side. This would result in one daughter cell having 4n or tetraploid number of chromosomes. Ideally, mitosis separates the chromosomes equally into the two daughter cells to have 2n each. If one cell has all chromosomes, it means that cell will have all the 4n.

For example, in a diploid human cell with 46 chromosomes (2n). Mitosis should occur in such a way that each daughter cell will have a diploid 46 number of chromosome (2n). However, if all the chromosome ends up in one cell during mitosis, that cell will have 92chromosomes, which is 4n or tetraploidy.

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Round seeds (R) are dominant to wrinkled seeds (r), and yellow seeds (Y) are dominant to green seeds (y). A plant of unknown gen
hammer [34]

Answer:

<h2>RrYy and rryy </h2>

Explanation:

1. As given; Round seeds (R)  are dominant on wrinkled seeds (r),

Yellow seeds (Y) are dominant on green seeds (g).

In a testcross, between an unknown genotype and a homozygous recessive with wrinkled and green seeds (rryy).

offspring are:  

Round and yellow are  53; genotype (R_Y_)

round and green are  49;  genotype (R_yy)  

wrinkle and yellow are 44;  genotype (rrY_)

wrinkled and green are  51 ; genotype  (rryy)

Here, the genotype of parents of these offspring would be RrYy and rryy.

6 0
3 years ago
How does mutation relate to variation
Anastasy [175]

Answer:

Mutation is the source for new genetic variation: Genetic variation is brought about by random mutation. Without mutation, genetic variation cannot occur. Mutation is a change in the genetic code in DNA and can lead to a change in the protein that is coded for that segment of DNA.

Explanation:

Mutations are changes to an organism's DNA and are an important driver of diversity in populations. Species evolve because of the accumulation of mutations that occur over time. ... This mutation has introduce a new allele into the population that increases genetic variation and may be passed on to the next generation.

8 0
3 years ago
Marianne is conducting an experiment on homeostasis in paramecium, which is a type of single-felled organism. Which of these obs
Drupady [299]

Hello. You did not present the answer options, which makes it difficult for you to receive a specific answer. However, I will try to help you in the best possible way.

One of the most common evidences that a paramecium is maintaining homeostasis is the pumping of water from the vacuoles present in its body.

The paramecium is a protozoan that lives in aquatic environments, mainly those composed of fresh water. The problem with this environment is that water is able to enter the paramecium organism in large quantities and this can promote the disruption of the organism through lysis of the cell. In this case, homeostasis must act quickly and pump water out of the body, through the cell vacuole.

Homeostasis is a regulatory system of the organism, which must promote the balance of the organism, whenever any external or internal factor tries to harm this balance.

8 0
3 years ago
One form of chromatin modification is acetylation, which is known to occur on positively charged histone tail amino acids, thus
Naya [18.7K]

Answer:

A. The tails do not interact with the DNA

Explanation:

The acetylation refers to the transfer of the acetyl group from Acetyl-CoA to the N-terminal of the histone protein.

Lysine residues (positively charged amino acid) are present at the end of the N-terminal of the histone protein which is neutralized by the acetyl group.

This loses the compaction between the positively charged histone and the negatively charged DNA and the DNA becomes more relaxed. This relaxed state allows the transcription factors to easily bind the DNA and therefore the DNA becomes transcriptionally active.

Thus, Option-A is correct

4 0
3 years ago
It is important that cells make the correct proteins necessary for survival. Which of these is true concerning the processes of
Talja [164]
C.) <span>Plants produce proteins much differently than animals.

Hope this helps!</span>
5 0
3 years ago
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