A I think sorry if I’m wrong
Facilitated diffusion does not use cellular energy.
Since the transportation of molecules occurs through the concentration gradient, it doesn’t use cellular energy for transportation of molecules.
Answer:
The correct answer is option D, that is, 27.
Explanation:
27 three-nucleotide codons would be possible when polynucleotide phosphorylase is supplemented to a solution of GTP, ATP, and UTP. As there are three nucleotides available, that is, guanine, adenine, and uracil and each codon comprise three nucleotides, thus, there would be a probability of (3)^3 codons, that is, 27.
Answer:
Barr bodies are small bodies that are dark staining bodies that show the inactivated X chromosome, these sex chromatin bodies attach to the membrane of the nucleus of interphase cells.
One less of the total number of X-chromosome (n-1) represents the number of Barr bodies.
Then,
The number of Barr bodies with Klinefelter would be:
Klinefelter (47,XXY): (n-1) = (2-1) = 1 Barr body as here two X chromosome present.
Similarly, for
Turner (45,XO): (n-1) = (1-1) = 0 Barr bodies (X chromosome = 1)
Now, as per the question, the bar bodies for karyotypes given
47,XYY: (n-1) = (1-1) = 0 Barr bodies
47,XXX: (n-1) = (3-1) = 2 Barr bodies
48,XXXX: (n-1) = (4-1) = 3 Barr bodies
