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larisa86 [58]
3 years ago
9

Answer please! .............................

Mathematics
1 answer:
TiliK225 [7]3 years ago
5 0

Answer:

A

Step-by-step explanation:

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The population of Tel Aviv, Israel was 413,000 in 2003. What is 413,000 rounded to ther nearest hundred-thousand?
musickatia [10]

Answer:

400,000

Step-by-step explanation:

Tel Aviv Population (2013) - 413,000

413,000 rounded to nearest hundred-thousand = 400,000

Final sum= 400,000. Hope this helps!

8 0
3 years ago
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PLS HELP WITH THIS ONE
olga2289 [7]

Answer:

460 ft^2 of carpet will be replaced

Step-by-step explanation:

You need to find the area of the room and then take away the area of the six bookcases

<u>Area of the room</u>

20*20=400ft^2

35-20=15ft

(15*20)/2=150ft^2

400+150=550ft^2 total room area

<u>Area of bookcases</u>

2.5*6*6=90ft^2 total bookcase area

<u>room area - bookcase area = carpet area</u>

550-90=460ft^2

4 0
2 years ago
Cot -90<br> trig function
Licemer1 [7]

Answer:

It doesn't exist,bro.

Step-by-step explanation:

5 0
3 years ago
Reflect over x-axis PLEASE HELP
Alinara [238K]
Point f ends up being (-4,-5)
point d is (-5,-1)
and point e is (4,-1)
6 0
3 years ago
A company uses three different assembly lines- A1, A2, and A3- to manufacture a particular component. Of thosemanufactured by li
hammer [34]

Answer:

The probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

Step-by-step explanation:

The three different assembly lines are: A₁, A₂ and A₃.

Denote <em>R</em> as the event that a component needs rework.

It is given that:

P (R|A_{1})=0.05\\P (R|A_{2})=0.08\\P (R|A_{3})=0.10\\P (A_{1})=0.50\\P (A_{2})=0.30\\P (A_{3})=0.20

Compute the probability that a randomly selected component needs rework as follows:

P(R)=P(R|A_{1})P(A_{1})+P(R|A_{2})P(A_{2})+P(R|A_{3})P(A_{3})\\=(0.05\times0.50)+(0.08\times0.30)+(0.10\times0.20)\\=0.069

Compute the probability that a randomly selected component needs rework when it came from line A₁ as follows:

P (A_{1}|R)=\frac{P(R|A_{1})P(A_{1})}{P(R)}=\frac{0.05\times0.50}{0.069}  =0.3623

Thus, the probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

6 0
3 years ago
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