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Lina20 [59]
2 years ago
6

Ken makes 75 cookies. He gives 35 of them to his classmates and 13 of them to his teachers. He brings the rest home. He brings h

ome
cookies.
Mathematics
2 answers:
velikii [3]2 years ago
6 0
75-35 =40 and 40-13 =27
So ken would bring home 27 cookies
IrinaVladis [17]2 years ago
3 0
27 cookies because 75 - 35=40. 40 - 13=27
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Find the value of x and y in the given parallelogram
frez [133]

Answer:

Step-by-step explanation:

9y-4 = 50

9y = 54

y= 6

9y-4+7x+xy = 180

9(6)-4+7x+6x= 180

54-4+13x = 180

13x+50 = 180

13x = 130

x = 10

6 0
3 years ago
How many permutations of the 26 letters of the English alphabet do not contain any of the strings fish, rat, or bird
NARA [144]

The number of permutations of the 26 letters of the English alphabet that do not contain any of the strings fish, rat, or bird is 402619359782336797900800000

Let

\mathcal{E}=\{\text{All lowercase letters of the English Alphabet}\}\\\\B=\overline{\{b,i,r,d\}} \cup \{bird\}\\\\F=\overline{\{f,i,s,h\}} \cup \{fish\}\\\\R=\overline{\{r,a,t\}} \cup \{rat\}\\\\FR=\overline{\{f,i,s,h,r,a,t\}} \cup \{fish,rat\}

Then

Perm(\mathcal{E})=\{\text{All orderings of all the elements of } \mathcal{E}\}\\\\Perm(B)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing bird}\}\\\\Perm(F)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing fish}\}\\\\Perm(R)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing rat}\}\\\\Perm(FR)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing both fish and rat}\}\\

Note that since

F \cap R=\varnothing, Perm(F)\cap Perm(R)\ne \varnothing

But since

B \cap R \ne \varnothing, Perm(B)\cap Perm(R)= \varnothing

and

B \cap F \ne \varnothing , Perm(B)\cap Perm(F)= \varnothing

Since

|\mathcal{E} |=26 \text{, then, } |Perm(\mathcal{E})|=26! \\\\|B|=26-4+1=23 \text{, then, } |Perm(B)|=23!\\\\|F|=26-4+1=23 \text{, then, } |Perm(F)|=23!\\\\|R|=26-3+1=24 \text{, then, } |Perm(R)|=24!\\\\|FR|=26-7+2=21 \text{, then, } |Perm(FR)|=21!\\

where |Perm(X)|=\text{number of possible permutations of the elements of X taking all at once}

and

|Perm(F) \cup Perm(R)| = |Perm(F)| + |Perm(R)| - |Perm(FR)|\\= 23!+24!- 21! \text{ possibilities}

What we are looking for is the number of permutations of the 26 letters of the alphabet that do  not contain the strings fish, rat or bird, or

|Perm(\mathcal{E})|-|Perm(B)|-|Perm(F)\cup Perm(R)|\\= 26!-23!-(23!+24!- 21!)\\= 402619359782336797900800000 \text{ possibilities}

This link contains another solved problem on permutations:

brainly.com/question/7951365

6 0
2 years ago
The function h(t) = 210 – 15t models the altitude of a hot air balloon over time t, in minutes.
Liula [17]
H(10) is the altitude of a hot air balloon overtime after 10 minutes. In order to find h(10)'s value, you just have to substitute 10 as t in the equation. h(10) and h(t) represents the value of y in a linear equation. So pretty much: h(10)= 210 - 15(10). If calculated correctly, h(10)=60.
8 0
3 years ago
Read 2 more answers
Jack bought 7 tickets to a movie he paid $7 for each adult ticket and and $4 for each child ticket jack spent $ 40 for the ticke
nydimaria [60]

Answer:

7

Step-by-step explanation:

4 0
3 years ago
Evaluate the expression.<br><br> (13^2 - 12^2) ÷ 5​
otez555 [7]
Answer:

5

Step-by-step explanation:

(13^2 - 12^2) ÷ 5

(169 - 144) ÷ 5

25 ÷ 5

5
5 0
2 years ago
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