Question

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Answer 1

Answer:

$\frac{180}{147}$

Step-by-step explanation:

• Simplify $(\frac{3}{-7} - \frac{11}{21} )$

$=> \frac{(-3 \times 3) - 11}{21}$

$=> \frac{-9 - 11}{21}$

$=> \frac{-20}{21}$

• Find the additive inverse of  $\frac{-20}{21}$ by using its property - "Sum of a number & its additive inverse is always zero". Assume that 'x' is an additive inverse of  $\frac{-20}{21}$.

$=> x + \frac{-20}{21} = 0$

$=> x = 0 - (-\frac{20}{21}) = \frac{20}{21}$

• Simplify $(\frac{9}{5} \div \frac{7}{5} )$

$=> \frac{9}{5} \times \frac{1}{\frac{7}{5} }$

$=> \frac{9}{5} \times \frac{5}{7}$

$=> \frac{9}{7}$

• Now, find the product of $\frac{9}{7}$ & $\frac{20}{21}$

$=> \frac{9}{7} \times \frac{20}{21}$

$=> \frac{180}{147}$