Answer:
- b (x, x - 3, 0)
- d Infinite Solutions
Step-by-step explanation:
1. A graphing calculator or any of several solvers available on the internet can tell you the reduced row-echelon form of the augmented matrix ...
![\left[\begin{array}{ccc|c}2&-2&-1&6\\-1&1&3&-3\\3&-3&2&9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D2%26-2%26-1%266%5C%5C-1%261%263%26-3%5C%5C3%26-3%262%269%5Cend%7Barray%7D%5Cright%5D)
is the matrix ...
![\left[\begin{array}{ccc|c}1&-1&0&3\\0&0&1&0\\0&0&0&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%26-1%260%263%5C%5C0%260%261%260%5C%5C0%260%260%260%5Cend%7Barray%7D%5Cright%5D)
The first row can be interpreted as the equation ...
x -y = 3
x -3 = y . . . . . add y-3
The second row can be interpreted as the equation ...
z = 0
Then the solution set is ...
(x, y, z) = (x, x -3, 0) . . . . matches selection B
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2. The second equation is 2 times the first equation, so the system of equations is dependent. There are infinite solutions.
Answer:
c
Step-by-step explanation:
36-29=

Answer:
(0,8)
Step-by-step explanation:
First, we must arrange this equation into slope-intercept form, or y=mx+b form.
Equation: y-8=2x
Add 8 to both sides: y=2x+8
Now that the equation is in slope-intercept form, it is easy to find the y-intercept, as it is just the b-value.
In this case, the b-value is 8, so the y-intercept is (0,8).
Let me know if this helps!
As the variation is direct we have:

Where,
k: proportionality constant
We must find the value of k.
For this we use the following data:
y is 18 when x is 5.
Substituting values we have:

From here, let's clear k:

Then, replacing values we have:

For x = 11 we have:
Answer:
An expression that can be used to find the value of y when x is 11 is:
When x = 11 we have:
Answer: Choice D
b greater-than 3 and StartFraction 2 over 15 EndFraction
In other words,
b > 3 & 2/15
or

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Explanation:
Let's convert the mixed number 2 & 3/5 into an improper fraction.
We'll use the rule
a & b/c = (a*c + b)/c
In this case, a = 2, b = 3, c = 5
So,
a & b/c = (a*c + b)/c
2 & 3/5 = (2*5 + 3)/5
2 & 3/5 = (10 + 3)/5
2 & 3/5 = 13/5
The inequality
is the same as 
---------------------
Let's multiply both sides by 15 to clear out the fractions

---------------------
Now isolate the variable b

Side note: Another way to go from 47/15 to 3 & 2/15 is to notice how
47/15 = 3 remainder 2
The 3 is the whole part while 2 helps form the fractional part. The denominator stays at 15 the whole time.