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vovangra [49]
3 years ago
14

How's your day :D I hope its goin well you amazing person :D

Computers and Technology
2 answers:
Rainbow [258]3 years ago
7 0

Answer:

You are an awesome and amazing person!!

Explanation:

madam [21]3 years ago
6 0

Answer:

its been going fine th 4 asking!! how's ur day going?!

Explanation:

ur an amazing person aswell :) :D

You might be interested in
Create a program which will input data into a pipe one character at a time. Count the number of characters as they are written i
LenKa [72]

Answer:

a)

#include<stdio.h>

#include<stdlib.h>

#include<fcntl.h>

#include<unistd.h>

 

#define BUFSIZE 16

int main(){

   //pipe descriptors

   char msg[BUFSIZE];

   char buf[BUFSIZE];

   int pipefd[2];

   if(pipe(pipefd) == -1){

       //pipe creation error

       perror("pipe");

       exit(EXIT_FAILURE);

   }

   //pipe creation successfull

   //write four messages

   sprintf(msg , "apple");

   write(pipefd[1], msg, BUFSIZE);

   printf("Written %s\n", msg);

   sprintf(msg , "boy");

   write(pipefd[1], msg, BUFSIZE);

   printf("Written %s\n", msg);

   sprintf(msg , "cat");

   write(pipefd[1], msg, BUFSIZE);

   printf("Written %s\n", msg);

   sprintf(msg , "dog");

   write(pipefd[1], msg, BUFSIZE);

   printf("Written %s\n", msg);

   //read

   read(pipefd[0], buf, BUFSIZE);

   printf("Read: %s\n", buf);

   read(pipefd[0], buf, BUFSIZE);

   printf("Read: %s\n", buf);

   read(pipefd[0], buf, BUFSIZE);

   printf("Read: %s\n", buf);

   read(pipefd[0], buf, BUFSIZE);

   printf("Read: %s\n", buf);

   close(pipefd[0]);

   close(pipefd[1]);

   return 0;

}

(b)

#include<stdio.h>

#include<stdlib.h>

#include<fcntl.h>

#include<unistd.h>

#include<wait.h>

#define BUFSIZE 16

int main(){

   //pipe descriptors

   char msg[BUFSIZE];

   char buf[BUFSIZE];

   int pipefd[2];

   if(pipe(pipefd) == -1){

       //pipe creation error

       perror("pipe");

       exit(EXIT_FAILURE);

   }

   //pipe creation successfull

   //write four messages

   if(fork() == 0){

       //this is child

       //close unused write end

       close(pipefd[1]);

       read(pipefd[0], buf, BUFSIZE);

       printf("This is child process reading first message. Content is %s\n", buf);

       read(pipefd[0], buf, BUFSIZE);

       printf("This is child process reading second message. Content is %s\n", buf);

       read(pipefd[0], buf, BUFSIZE);

       printf("This is child process reading third message. Content is %s\n", buf);

       read(pipefd[0], buf, BUFSIZE);

       printf("This is child process reading fourth message. Content is %s\n", buf);

       close(pipefd[0]);

       //exit from child

       exit(EXIT_SUCCESS);

   }

   //this is parent process

   //close unused read end

   close(pipefd[0]);

   sprintf(msg , "apple");

   printf("This is parent process. Writing first message into pipe\n");

   write(pipefd[1], msg, BUFSIZE);

   sprintf(msg , "boy");

   printf("This is parent process. Writing second message into pipe\n");

   write(pipefd[1], msg, BUFSIZE);

   sprintf(msg , "cat");

   printf("This is parent process. Writing third message into pipe\n");

   write(pipefd[1], msg, BUFSIZE);

   sprintf(msg , "dog");

   printf("This is parent process. Writing fourth message into pipe\n");

   write(pipefd[1], msg, BUFSIZE);

   close(pipefd[1]);

   //wait for child

   wait(NULL);

   return 0;

}

(c)

#include<stdio.h>

#include<stdlib.h>

#include<fcntl.h>

#include<unistd.h>

#include<sys/wait.h>

#include<sys/types.h>

#include<signal.h>

typedef struct sigaction Sigaction;

unsigned long long size = 0;

void alarmhandler(int sig){

   //alarm fired writing blocked

   printf("Write blocked after %llu characters\n", size);

   exit(EXIT_SUCCESS);

}

int main(){

   //pipe descriptors

   int pipefd[2];

   if(pipe(pipefd) == -1){

       //pipe creation error

       perror("pipe");

       exit(EXIT_FAILURE);

   }

   //install handler

   sigset_t mask , prev;

   sigemptyset(&mask);

   sigaddset(&mask , SIGALRM);

   sigprocmask(SIG_BLOCK , &mask , &prev);

   Sigaction new_action;

   sigemptyset(&new_action.sa_mask);

   new_action.sa_flags = SA_RESTART;

   new_action.sa_handler = alarmhandler;

   sigaction(SIGALRM , &new_action , NULL);

   sigprocmask(SIG_SETMASK , &prev, NULL);

   while(1){

     

       //print size on multiple of 4

       if(size != 0 && size % 1024 == 0){

           printf("%llu characters in pipe\n", size);

       }

       //reset previous alarm

       alarm(0);

       //set new alarm for 5 seconds

       alarm(5);

       //write to pipe one character

       write(pipefd[1], "A", sizeof(char));

       size++;

   }

   return 0;

}

Explanation:

Output for a, b, c are pasted accordingly

4 0
3 years ago
The Syntax NPV formula includes the Rate, The Cash Flows, the number of payments, and the Future
Tems11 [23]

Answer:

False

Explanation:

NPV stands for Net Present Value, it is an important term in finance as it used to determine the value of money or investment based on a series of cashflows and specified discount rate. Excel provides a functions which aids easy calculation of the Net Present value of money or investment using the NPV formula. The syntax forbthe NPV formula is :

=NPV(rate,value 1, [value 2],...)

This formular requires only tow key parameters ; the discount rate, which comes first and the cashflows, which is designated in the syntax as values ; the cashflows is usually placed in a range of cells in excel and the cell range is inputed in the formular. Hence, the number of payments and future value aren't part of the NPV syntax.

5 0
3 years ago
Each cable type can transport data at a particular speed only so far before its signals begin to weaken past the point that a re
Nataliya [291]

Answer:

attenuation

Explanation:

Based on the information provided within the question it can be said that the phenomenon that is being described in this scenario is known as attenuation. In the context of physics, this refers to the gradual loss of intensity of something when traveling through a medium. Which in this case would be the data signals travelling through the cables.

7 0
3 years ago
In the library 6 students are working on math. of those 6 students 2/3 of them are working on fractions. how many students are w
zmey [24]
Explanation:
The word "of" in a fraction word problem USUALLY means to multiply. So we multiply 6 x 2/3

6 2 12
- x - = - = 4
1 3 3
6 0
3 years ago
Jose has 3/5 kilogram of peppermints and 2/3 kilogram of candy canes. How many kilograms of candy does he have?
yarga [219]

Answer:

\frac{19}{15}\\

≅ 1.267

Explanation:

\frac{3}{5} +\frac{2}{3} \\\\= \frac{9}{15} + \frac{10}{15} \\\\= \frac{9+10}{15} \\\\= \frac{19}{15} \\\\= 1.267

6 0
2 years ago
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