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Damm [24]
3 years ago
10

Marta invests $8500 in a new savings account which earns 5.0% annual interest, compounded continuously. What will be the value o

f her investment after 5 years?

Mathematics
1 answer:
Mariulka [41]3 years ago
4 0

Given:

Investment = $8500

Rate of interest = 5.0%

Time = 5 years

Compounded continuously

To find:

The value of investment after 5 years.

Solution:

Rate = 5.0%

        =\frac{5}{100}

Rate = 0.05

Compound interest formula if interest compounded continuously:

A = P e^{rt}

where P is the investment and r is the rate and t is the time.

A = 8500 \times  e^{0.05 \times 5}

A = 8500 \times  e^{0.25}

The value of e^{0.25}=1.284025.

A = 8500 \times  1.284025

A=10914.21

The value of the investment after 5 years is $10914.21.

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Answer:

Sally's temperature is 97.27 °F.

Step-by-step explanation:

All the information given in the question tells us that the human body temperatures are normally distributed with a population's mean = 98.20°F and a standard deviation = 0.62°F.

The question gives us Sally's temperature in a <em>z-score</em>. We have to remember that the <em>standard normal distribution</em> is a particular case of a <em>normal distribution</em> where the mean = 0 and the standard deviation = 1.

Using <em>the standard normal distribution,</em> we can determine every probability associated with a normal distribution "transforming" the raw scores, coming from normally distributed data, into z-scores.

A z-score gives us the distance from the population's mean and is in standard deviation units. So, a z = 1.5 tells us that the value is 1.5 standard deviations <em>above the mean</em>. Conversely, a z = -1.5 tells us that the raw score is also 1.5 standard deviation from the mean, but in the opposite direction, that is, <em>below the mean</em>.

The formula for a z-score is as follows:

\\ z = \frac{x - \mu}{\sigma} (1)

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\\ x\;is\;the\;raw\;score.

\\ \mu\;is\;the\;population\;mean.

\\ \sigma\;is\;the\;population\;standard\;deviation.

Then to find <em>x </em>(or the raw score, that is, Sally's temperature), we need to solve the formula (1) for it to finally solve the question.

Then

\\ \mu = 98.20^\circF °F

\\ \sigma = 0.62^\circF °F

\\ z = -1.5

Thus (with no units)

\\ -1.5 = \frac{x - 98.20}{0.62}

\\ (-1.5*0.62) = x - 98.20

\\ (-1.5*0.62) + 98.20 = x

\\ x = (-1.5*0.62) + 98.20

\\ -0.93 + 98.20

\\ x = 97.27°F

Thus, Sally's temperature is \\ x = 97.27°F (rounding the answer to the nearest hundredth).

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