Answer:
x ≥ 7
Step-by-step explanation:
|x - 7| = x - 7
A. For each absolute, find the intervals
x - 7 ≥ 0 x - 7 < 0
x ≥ 7 x < 7
If x ≥ 7, |x - 7| = x - 7 > 0.
If x < 7, |x - 7| = x - 7 < 0. No solution.
B. Solve for x < 7
Rewrite |x - 7| = x - 7 as
+(x - 7) = x - 7
x - 7 = x - 7
-x + 14 = x
14 = 2x
x = 7
7 ≮7. No solution
C. Solve for x ≥ 7
Rewrite |x - 7| = x - 7 as
+(x - 7) = x - 7
x - 7 = x - 7
True for all x.
D. Merge overlapping intervals
No solution or x ≥ 7
⇒ x ≥ 7
The diagram below shows that the graphs of y = |x - 7| (blue) and of y = x - 7 (dashed red) coincide only when x ≥ 7.
Answer:
466mEq
Step-by-step explanation:
First, we need to know the concentration of NaCl in a normal saline solution, this is by definition 0.9%, meaning we have 0.9g of NaCl per 100ml of solution, we want to know how much NaCl we have in 3L (3000ml):
So, we have 27000mg in 3L of normal saline solution.
Now, acording to our milliequivalent (mEq) equation (
) where pE is de molecular mass of NaCl divided by their charges, in this case 1:
Finally we substitute in the mEq formula:
I hope you find this information useful! Good luck!
Step-by-step explanation:
Simple interest =P (1+. R )^n
/100
Where P is the amount
R is rate (%)
n is number of years
So if you are given months your divide ➗ the number of months by 12 years
2710 *(1+ [ 3.8/100])^3/12
Answer:
3 gallons.
Step-by-step explanation:
We have been given that Jen picked 3/4 of a gallon of strawberries in a half an hour.
Let us convert our given time in minutes.
1 hour= 60 minutes.
1/2 hour= 30 minutes.
So 2 hours= 120 minutes.
Let us find the number of gallons of strawberries picked by Jen in 30 minutes by dividing 3/4 by 30.
Now let us multiply 1/40 by 120 to find the number of gallons of strawberries picked by Jen in 120 minutes(2 hours).
Therefore, Jen picked 3 gallons of strawberries in 2 hours.
Answer:
1= 1
2=11
3=7
Step-by-step explanation:
subtract 6 from the input so
7-6=1
11-6=5 so input 11
13-6=7
