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Nadya [2.5K]
3 years ago
14

Solve for x. x^5 +x^3 +2x=2x^4 +x^2 +1. There are imaginary solutions too.

Mathematics
1 answer:
Sonja [21]3 years ago
8 0

Answer:

i got like 4 different answers so x=1, x=-1 x=2 and x=0 i hope i helped

Step-by-step explanation:

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Anvisha [2.4K]

Answer:

Without the “ur mom” the answer would be 164. But since i am a very smart intellectual i know that “ur mom” could have an infinite amount of meanings which means in number form it would be infinite. There is no correct answer to this question and i know this because i am very smart. At least that’s what my grandma says.

Step-by-step explanation:

4 0
3 years ago
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Hệ phương trình <br> 1/x + 1/y = 5/24 <br> 4/x + 3/y = 3/4
LiRa [457]

Step-by-step explanation:

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8 0
3 years ago
F(x) = 2x3 + 7x2 – 4x – 5
qaws [65]

Answer:

Its 3

Step-by-step explanation:

7 0
3 years ago
What is the probability that a randomly selected member of a normally distributed population will lie more than 1.8 standard dev
Helen [10]

Answer:

P(X> \mu +1.8\sigma)=P(\frac{X-\mu}{\sigma}>\frac{\mu +1.8\sigma-\mu}{\sigma})=P(Z>1.8)

And we can find this probability using the complement rule:

P(z>1.8)=1-P(z

And using the normal standard distirbution table or excel we got:

P(z>1.8)=1-P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the variable if interest of a population, and for this case we know the distribution for X is given by:

X \sim N(\mu,\sigma)  

We are interested on this probability

P(X>\mu +1.8 \sigma)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X> \mu +1.8\sigma)=P(\frac{X-\mu}{\sigma}>\frac{\mu +1.8\sigma-\mu}{\sigma})=P(Z>1.8)

And we can find this probability using the complement rule:

P(z>1.8)=1-P(z

And using the normal standard distirbution table or excel we got:

P(z>1.8)=1-P(z

5 0
4 years ago
A reasonable estimate of the
lyudmila [28]

Answer:

t

f

t

t

f

f

Step-by-step explanation:

6 0
3 years ago
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