Question

Write 6(x – 5)4 + 4(x – 5)2 + 6 = 0 in the form of a quadratic by using substitution.

Answer 1

We are given the equation:

$6(x-5)^{4}+4(x-5)^{2}+6=0$..........(1)

Now we have to write it in quadratic form using substitution.

The general form of quadratic equation is given by:

$ax^{2}+bx+c=0$

So let us say

$(x-5)^{2}=u$.......(2)

Plugging the value of (x-5)² from equation (2) in (1),

$6u^{2}+4u+6=0$

Answer : Option B. $6u^{2}+4u+6=0$