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Pavel [41]
3 years ago
6

A ball is thrown from the top row of seats in a stadium. The function h(t)=-16t2+48t+160 gives the height, t, in feet, of the ba

ll t seconds after it is thrown. How long will it be before the ball hits the ground?
Mathematics
1 answer:
yaroslaw [1]3 years ago
4 0

Answer:

t = 5 s

Step-by-step explanation:

The function that gives the height in feet of the ball t seconds after it is thrown is :

h(t)=-16t^2+48t+160

We need to find how long will it be before the ball hits the ground. When it hits the ground, its height will be equal to 0.

So,

-16t^2+48t+160=0

We need to solve this equation. When we solve, we get its solution as shown in the figure. We can see that t = -2 s and t = 5 s.

t = -2 s is not possible.

Hence, the ball will hit the ground before 5 seconds.

You might be interested in
Which expression can be used to represent the volume of this prism?
BARSIC [14]

Answer:

48 x 3 units

Step-by-step explanation:

6 x 8 is 48

48 x height

Height is 3 units

8 0
3 years ago
Read 2 more answers
A woman deposit $100 into her son saving account on his first birthday on his second birthday she deposits $125 and $150 on his
OleMash [197]
This is just showing what I did.
100=1     125=2     150=3     175=4     200=5     225=6     250=7     275=8     300=9     325=10   350=11    375=12  400=13   425=14    450=15   475=16   500=17. So on the son's 17th birthday his mom deposited $500 in her son's saving account. Hope I helped!
5 0
3 years ago
In 2002, Tim was twice as old as Sue. In 1997 the sum of their ages was 32. In what year will Sue's age be three-fourths Tim's a
xxMikexx [17]

Answer:

Year 2030.

Step-by-step explanation

In 1997, Let Tim's age = <em>X</em> years

In 1997, Let Sue's age = <em>Y</em> years

After 5 years in 2002, Tim's age = (<em>X+ 5) </em>years

After 5 years in 2002, Sue's age = <em>(Y + 5)</em> years

Now, According to question,

<em>X </em>+ <em>Y</em> = 32    (sum of their ages) .......(1)

<em>Y </em>= 32 -<em> X</em>

(X + 5) = 2 (Y + 5) .......(2)

Substituting the value of <em>Y</em> in (2)

<em>X </em>+ 5 = 2 (32 - <em>X </em>+ 5)

<em>X </em>+ 5 = 2 (37 - <em>X </em>)

<em>X </em>+ 5 = 74 - 2<em>X </em>

3<em>X </em>=<em> </em>69

<em>X </em>= 69/3 = 23

Now ∵<em> Y</em> = 32 - <em>X  </em>and<em> X = </em>23

∴ <em>Y</em> = 32 - 23 = 9

So, In 1997, Tim's age = 23 years and Sue's age = 9 years.

Let the year in which Sue's age will be three-fourth times of Tim's age be t.

Sue's age after<em> t </em>years = (9 +<em> t) </em>years.

Tim's age after<em> t</em> years = (23 + <em>t</em>) years

According to question,

(9 + t) = \frac{3}{4} \times(23 + t)

4 (9 + t) = 3 (23 + t)

36 + 4t = 69 + 3t

<em>4t - 3t = 69 - 36</em>

<em>t = 33</em>

The Year in which Sue's age will be three-fourth times of Tim's age is:

= (1997 + 33) = 2030.

4 0
4 years ago
For #12 and #13, make a function table of values for each function with the given input values.
g100num [7]
#12. When x = 4, y = 5(4) - 1 = 20 - 1 = 19
         when x = 12, y = 5(12) - 1 = 60 - 1 = 59
         when x = 0, y = 5(0) - 1 = 0 - 1 = -1
         when x = 0.5, y = 5(0.5) - 1 = 2.5 - 1 = 1.5
8 0
3 years ago
An airline estimates that 94% of people booked on their flights actually show up. If the airline books 68 people on a flight for
Setler79 [48]

Answer:

0.0788

Step-by-step explanation:

In this case the final probability will be the sum of the probability of when there are 67 more reserves when there are 68.

That is to say:

P (f) = P (x = 67) + P (x = 68)

n = 68; p = 0.94

Now we calculate each one:

P (x) = nCx * (p ^ x) * [(1 - p) ^ (n-x)]

nCx = n! / (x! * (n - x)!)

Knowing the formula, we replace:

P (67) = 68C67 * (0.94 ^ 67) * [(1 - 0.94) ^ (68-67)]

nCx = 68! / (67! * (68 - 67)!) = 68! / 67! = 68

P (67) = 68 * (0.0158) * (0.06) = 0.064

Now for x = 68

P (68) = 68C68 * (0.94 ^ 68) * [(0.0641 - 0.94) ^ (68-68)]

nCx = 68! / (68! * (68 - 68)!) = 1

P (68) = 1 * (0.0148) * (1) = 0.0148

Then replacing in the main formula:

P (f) = P (x = 67) + P (x = 68)

P (f) = 0.064 + 0.0148

P (f) = 0.0788

8 0
3 years ago
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